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The differential equation whose solution is Ax2 + By2 = 1 where A and B are arbitrary constants is ofa)second order and second degreeb)first order and second degreec)first order and first degreed)second order and first degreeCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The differential equation whose solution is Ax2 + By2 = 1 where A and B are arbitrary constants is ofa)second order and second degreeb)first order and second degreec)first order and first degreed)second order and first degreeCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The differential equation whose solution is Ax2 + By2 = 1 where A and B are arbitrary constants is ofa)second order and second degreeb)first order and second degreec)first order and first degreed)second order and first degreeCorrect answer is option 'D'. Can you explain this answer?.

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