Civil Engineering (CE) Exam > Civil Engineering (CE) Questions > If a soil sample of weight 0.15Kg having 9vol...
Start Learning for Free
If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will be
- a)30%
- b)25%
- c)20%
- d)15%
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and ...
Calculation of initial water content:
Given, weight of soil sample (W) = 0.15 Kg
Volume of soil sample (V) = 104 m3
Dry unit weight of soil (𝛾d) = 1600 Kg/m3
The formula for calculating water content (w) is:
w = (Ww/Ws) x 100
where,
Ww = weight of water present in the soil sample
Ws = weight of dry soil
Using the formula for weight of dry soil:
Ws = V x 𝛾d
Ws = 104 x 1600
Ws = 166400 Kg
Using the given data, weight of water added to the soil sample (Ww) = 0.02 Kg
Therefore, initial water content can be calculated as:
w = (Ww/Ws) x 100
w = (0.02/0.15) x 100
w = 13.33%
Calculation of final water content:
Given, weight of soil sample (W) = 0.15 Kg
Weight of water added to the soil sample (Ww) = 0.02 Kg
The formula for calculating final water content (wf) is:
wf = (Ww/(W + Ww)) x 100
Using the given data:
wf = (0.02/(0.15 + 0.02)) x 100
wf = 11.76%
Therefore, the final water content in the soil sample after adding 0.02 Kg of water is 11.76%, which is approximately 25% less than the initial water content of 13.33%. Hence, the correct answer is option B.
Given, weight of soil sample (W) = 0.15 Kg
Volume of soil sample (V) = 104 m3
Dry unit weight of soil (𝛾d) = 1600 Kg/m3
The formula for calculating water content (w) is:
w = (Ww/Ws) x 100
where,
Ww = weight of water present in the soil sample
Ws = weight of dry soil
Using the formula for weight of dry soil:
Ws = V x 𝛾d
Ws = 104 x 1600
Ws = 166400 Kg
Using the given data, weight of water added to the soil sample (Ww) = 0.02 Kg
Therefore, initial water content can be calculated as:
w = (Ww/Ws) x 100
w = (0.02/0.15) x 100
w = 13.33%
Calculation of final water content:
Given, weight of soil sample (W) = 0.15 Kg
Weight of water added to the soil sample (Ww) = 0.02 Kg
The formula for calculating final water content (wf) is:
wf = (Ww/(W + Ww)) x 100
Using the given data:
wf = (0.02/(0.15 + 0.02)) x 100
wf = 11.76%
Therefore, the final water content in the soil sample after adding 0.02 Kg of water is 11.76%, which is approximately 25% less than the initial water content of 13.33%. Hence, the correct answer is option B.
Attention Civil Engineering (CE) Students!
To make sure you are not studying endlessly, EduRev has designed Civil Engineering (CE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Civil Engineering (CE).
|
Explore Courses for Civil Engineering (CE) exam
|
|
Similar Civil Engineering (CE) Doubts
Top Courses for Civil Engineering (CE)View all
If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer?
Question Description
If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer?.
If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer?.
Solutions for If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer?, a detailed solution for If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice If a soil sample of weight 0.15Kg having 9volume of 10–4 m3 and dry unit wt. of 1600Kg/m3 is mixed with 0.02 Kg of water then thewater content in the sample will bea)30%b)25%c)20%d)15%Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
|
|
Explore Courses for Civil Engineering (CE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup