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Consider the vector field  and surface integral  where S be is the surface consists of the three z = 5 - x2- y2, 1 < z < 5 on the top ; x2 + y2 = 1 , 0 < z < 1 on the bottom ; z = 0 base. Then the flux of across the surface S is  _______
    Correct answer is '0'. Can you explain this answer?
    Verified Answer
    Consider the vector fieldand surface integralwhereS be is the surface ...
    We know flux of across S is given by the surface integral 
    Here S be a closed surface So we can apply gauss divergence theorem.

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    Most Upvoted Answer
    Consider the vector fieldand surface integralwhereS be is the surface ...
    We know flux of across S is given by the surface integral 
    Here S be a closed surface So we can apply gauss divergence theorem.

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    Consider the vector fieldand surface integralwhereS be is the surface consists of the threez = 5 - x2- y2, 1 < z < 5 on the top ; x2 + y2 = 1 , 0<z < 1 on the bottom ; z = 0 base. Then the flux of across the surface S is _______Correct answer is '0'. Can you explain this answer?
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    Consider the vector fieldand surface integralwhereS be is the surface consists of the threez = 5 - x2- y2, 1 < z < 5 on the top ; x2 + y2 = 1 , 0<z < 1 on the bottom ; z = 0 base. Then the flux of across the surface S is _______Correct answer is '0'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about Consider the vector fieldand surface integralwhereS be is the surface consists of the threez = 5 - x2- y2, 1 < z < 5 on the top ; x2 + y2 = 1 , 0<z < 1 on the bottom ; z = 0 base. Then the flux of across the surface S is _______Correct answer is '0'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the vector fieldand surface integralwhereS be is the surface consists of the threez = 5 - x2- y2, 1 < z < 5 on the top ; x2 + y2 = 1 , 0<z < 1 on the bottom ; z = 0 base. Then the flux of across the surface S is _______Correct answer is '0'. Can you explain this answer?.
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