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The number of photon emitted per second by a 40W source of mono chromatic light of wavelength 6000Å is given by x × 1020. Find the value of x.
    Correct answer is '1.206'. Can you explain this answer?
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    The number of photon emitted per second by a 40Wsource of mono chromat...
    To find the number of photons emitted per second by a 40W source of monochromatic light of wavelength 6000 Å (angstroms), we can use the formula:

    Number of photons = Power / Energy of each photon

    First, we need to find the energy of each photon using the formula:

    Energy of each photon = Planck's constant * speed of light / wavelength

    Planck's constant (h) = 6.63 x 10^(-34) Js
    Speed of light (c) = 3 x 10^8 m/s
    Wavelength (λ) = 6000 Å = 6000 x 10^(-10) m (converting angstroms to meters)

    Energy of each photon = (6.63 x 10^(-34) Js) * (3 x 10^8 m/s) / (6000 x 10^(-10) m)

    Energy of each photon = 3.315 x 10^(-19) J

    Now, we can calculate the number of photons using the formula:

    Number of photons = Power / Energy of each photon

    Power = 40 W

    Number of photons = 40 W / (3.315 x 10^(-19) J)

    Number of photons = 1.207 x 10^20 photons

    Therefore, the number of photons emitted per second by a 40W source of monochromatic light of wavelength 6000 Å is approximately 1.207 x 10^20 photons.
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