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8 men and 12 boys can finish a piece of work in 10 days while 6 men and 8 boys can finish the work in 14 days. find the time taking by 1 man alone and 1 boy alone to finish the same work.
  • a)
    120, 130       
  • b)
    140, 280       
  • c)
    240, 280       
  • d)
    100, 120     
Correct answer is option 'B'. Can you explain this answer?
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Given: 8 men and 12 boys can finish a piece of work in 10 days while 6 men and 8 boys can finish the work in 14 days.

To find: Time taken by 1 man alone and 1 boy alone to finish the same work.

Let the work be W and let 1 man's 1 day work be M and 1 boy's 1 day work be B.

From the given data, we can form the following equations:

Equation 1: 8M + 12B = W/10 (combined work of 8 men and 12 boys for 10 days to finish the work)
Equation 2: 6M + 8B = W/14 (combined work of 6 men and 8 boys for 14 days to finish the work)

Solving these two equations simultaneously, we get:

M = 20/W and B = 35/W

Now, we can find the time taken by 1 man alone and 1 boy alone to finish the work as follows:

Time taken by 1 man alone = W/M = W/(20/W) = W^2/20
Time taken by 1 boy alone = W/B = W/(35/W) = W^2/35

Therefore, the answer is option B: 140, 280.
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8 men and 12 boys can finish a piece of work in 10 days while 6 men and 8 boys can finish the work in 14 days. find the time taking by 1 man alone and 1 boy alone to finish the same work.a)120, 130b)140, 280c)240, 280d)100, 120Correct answer is option 'B'. Can you explain this answer?
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