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The SNR of an FM limiter - descriminator demodulator is? When input signal strength = 0.5W, maximum frequency deviation = 60 k Hz, base band signal cut off frequency = 15Khz, received white Gaussian noise power sprectral density = 10-8 W/Hz and the average power of modulating signal is = 0.1W
- a)36.08dB
- b)26.07dB
- c)46.07dB
- d)30dB
Correct answer is option 'B'. Can you explain this answer?
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The SNR of an FM limiter - descriminator demodulator is? When input si...
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Understanding SNR in FM Limiter-Discriminator Demodulator
The Signal-to-Noise Ratio (SNR) in an FM demodulator is crucial for understanding the system's performance under noise conditions. Here’s a breakdown of the calculation:
Given Parameters:
- Input Signal Power (P) = 0.5 W
- Maximum Frequency Deviation (Δf) = 60 kHz
- Baseband Signal Cut-off Frequency (fc) = 15 kHz
- Noise Power Spectral Density (N0) = 10^(-8) W/Hz
- Average Power of Modulating Signal (Pm) = 0.1 W
Calculating SNR:
1. Calculate the Noise Power (N):
- Noise Power (N) = N0 * Bandwidth
- Bandwidth for FM = 2 * (Δf + fc) = 2 * (60 kHz + 15 kHz) = 150 kHz
- N = 10^(-8) W/Hz * 150,000 Hz = 1.5 * 10^(-3) W = 0.0015 W
2. Calculate the SNR:
- SNR = Signal Power / Noise Power = 0.5 W / 0.0015 W = 333.33
3. Convert SNR to dB:
- SNR(dB) = 10 * log10(333.33) ≈ 26.07 dB
Conclusion:
- The calculated SNR for the FM limiter-discriminator demodulator is approximately 26.07 dB, which matches option 'B'.
Final Note:
- Understanding these calculations helps in designing efficient communication systems, ensuring they can handle the noise while maintaining signal integrity.
The Signal-to-Noise Ratio (SNR) in an FM demodulator is crucial for understanding the system's performance under noise conditions. Here’s a breakdown of the calculation:
Given Parameters:
- Input Signal Power (P) = 0.5 W
- Maximum Frequency Deviation (Δf) = 60 kHz
- Baseband Signal Cut-off Frequency (fc) = 15 kHz
- Noise Power Spectral Density (N0) = 10^(-8) W/Hz
- Average Power of Modulating Signal (Pm) = 0.1 W
Calculating SNR:
1. Calculate the Noise Power (N):
- Noise Power (N) = N0 * Bandwidth
- Bandwidth for FM = 2 * (Δf + fc) = 2 * (60 kHz + 15 kHz) = 150 kHz
- N = 10^(-8) W/Hz * 150,000 Hz = 1.5 * 10^(-3) W = 0.0015 W
2. Calculate the SNR:
- SNR = Signal Power / Noise Power = 0.5 W / 0.0015 W = 333.33
3. Convert SNR to dB:
- SNR(dB) = 10 * log10(333.33) ≈ 26.07 dB
Conclusion:
- The calculated SNR for the FM limiter-discriminator demodulator is approximately 26.07 dB, which matches option 'B'.
Final Note:
- Understanding these calculations helps in designing efficient communication systems, ensuring they can handle the noise while maintaining signal integrity.
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The SNR of an FM limiter - descriminator demodulator is? When input signal strength = 0.5W, maximum frequency deviation = 60 k Hz, base band signal cut off frequency = 15Khz, received white Gaussian noise power sprectral density = 10-8 W/Hz and the average power of modulating signal is = 0.1Wa)36.08dB b)26.07dBc)46.07dB d)30dBCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2025 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The SNR of an FM limiter - descriminator demodulator is? When input signal strength = 0.5W, maximum frequency deviation = 60 k Hz, base band signal cut off frequency = 15Khz, received white Gaussian noise power sprectral density = 10-8 W/Hz and the average power of modulating signal is = 0.1Wa)36.08dB b)26.07dBc)46.07dB d)30dBCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The SNR of an FM limiter - descriminator demodulator is? When input signal strength = 0.5W, maximum frequency deviation = 60 k Hz, base band signal cut off frequency = 15Khz, received white Gaussian noise power sprectral density = 10-8 W/Hz and the average power of modulating signal is = 0.1Wa)36.08dB b)26.07dBc)46.07dB d)30dBCorrect answer is option 'B'. Can you explain this answer?.
The SNR of an FM limiter - descriminator demodulator is? When input signal strength = 0.5W, maximum frequency deviation = 60 k Hz, base band signal cut off frequency = 15Khz, received white Gaussian noise power sprectral density = 10-8 W/Hz and the average power of modulating signal is = 0.1Wa)36.08dB b)26.07dBc)46.07dB d)30dBCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2025 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The SNR of an FM limiter - descriminator demodulator is? When input signal strength = 0.5W, maximum frequency deviation = 60 k Hz, base band signal cut off frequency = 15Khz, received white Gaussian noise power sprectral density = 10-8 W/Hz and the average power of modulating signal is = 0.1Wa)36.08dB b)26.07dBc)46.07dB d)30dBCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The SNR of an FM limiter - descriminator demodulator is? When input signal strength = 0.5W, maximum frequency deviation = 60 k Hz, base band signal cut off frequency = 15Khz, received white Gaussian noise power sprectral density = 10-8 W/Hz and the average power of modulating signal is = 0.1Wa)36.08dB b)26.07dBc)46.07dB d)30dBCorrect answer is option 'B'. Can you explain this answer?.
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The SNR of an FM limiter - descriminator demodulator is? When input signal strength = 0.5W, maximum frequency deviation = 60 k Hz, base band signal cut off frequency = 15Khz, received white Gaussian noise power sprectral density = 10-8 W/Hz and the average power of modulating signal is = 0.1Wa)36.08dB b)26.07dBc)46.07dB d)30dBCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The SNR of an FM limiter - descriminator demodulator is? When input signal strength = 0.5W, maximum frequency deviation = 60 k Hz, base band signal cut off frequency = 15Khz, received white Gaussian noise power sprectral density = 10-8 W/Hz and the average power of modulating signal is = 0.1Wa)36.08dB b)26.07dBc)46.07dB d)30dBCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The SNR of an FM limiter - descriminator demodulator is? When input signal strength = 0.5W, maximum frequency deviation = 60 k Hz, base band signal cut off frequency = 15Khz, received white Gaussian noise power sprectral density = 10-8 W/Hz and the average power of modulating signal is = 0.1Wa)36.08dB b)26.07dBc)46.07dB d)30dBCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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