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Let  the set of natural numbers, define a relation on  is even  then
  • a)
    R is an equivalence relation
  • b)
    these are only two class of with respect to this relation
  • c)
  • d)
Correct answer is option 'A,C'. Can you explain this answer?
Most Upvoted Answer
Letthe set of natural numbers, define a relation on is eventhena)R is ...
If option B said this....
There are only two distinct equivalence classes with respect to this relation.
then it would definitely be correct.
Community Answer
Letthe set of natural numbers, define a relation on is eventhena)R is ...
Let, a+b =2k
b+c = 2m
a+b+b+c = 2k+2m
a+c = 2(k+m-b) which is also even, so it is transitive .
a+ a = 2a , so it is reflexive.
a+b =b+a ,so it is symmetric.
so it is equivalence relation.

Now, cl(2) means the number related to 2 so the number added with 2 gives a even number ,
cl(2) is the set of all even natural numbers.
other side, cl(1) means the number added with 1 ,gives an even number,
cl(1) means all the odd natural numbers
so intersection of cl(1) and cl (2) is phi.
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Letthe set of natural numbers, define a relation on is eventhena)R is an equivalence relationb)these are only two class of with respect to this relationc)d)Correct answer is option 'A,C'. Can you explain this answer?
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