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29. A body of mass m1 is moving with velocity u. It collides with another stationary body of mass m2. They get embedded. At the point of collision, the velocity of the system :
- a)increases
- b)decreases but does not become zero
- c)remains same
- d)zero
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
29. A body of mass m1 is moving with velocity u. It collides with anot...
The correct answer is Option B
Just before the collision the velocity of the center of mass will be
after the collision if the system moves with velocity V0 then on conserving the momentum
we will get m1V + 0=(m1 + m2)V0
or V0 =
we can notice that both V0 and u are the same, due to absence of external force on the system.
Just before the collision the velocity of the center of mass will be
after the collision if the system moves with velocity V0 then on conserving the momentum
we will get m1V + 0=(m1 + m2)V0
or V0 =
we can notice that both V0 and u are the same, due to absence of external force on the system.Most Upvoted Answer
29. A body of mass m1 is moving with velocity u. It collides with anot...
Apply momentum conservation,
p(initial)=p(final)
m1u=(m1+m2)v
v=m1u/(m1+m2)
so, velocity decreases bcoz (m1+m2)>m1
p(initial)=p(final)
m1u=(m1+m2)v
v=m1u/(m1+m2)
so, velocity decreases bcoz (m1+m2)>m1
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Community Answer
29. A body of mass m1 is moving with velocity u. It collides with anot...
Explanation:
When two bodies collide, their velocities can change due to the conservation of momentum and energy. In this case, we have a body of mass m1 moving with velocity u colliding with another stationary body of mass m2.
Conservation of Momentum:
According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.
Before the collision:
Momentum of body 1 = m1 * u
Momentum of body 2 = 0 (as it is stationary)
Total momentum before the collision = m1 * u + 0 = m1 * u
After the collision:
Since the bodies get embedded, they move together with a common velocity v.
Total momentum after the collision = (m1 + m2) * v
According to the law of conservation of momentum:
m1 * u = (m1 + m2) * v
Simplifying the equation:
u = (m1 + m2) * v / m1
Conclusion:
From the equation derived above, we can see that the velocity of the system after the collision, v, is dependent on the masses of both bodies and the initial velocity of body 1, u.
Since the mass of the system after the collision, (m1 + m2), is greater than the mass of body 1, m1, and the velocity u is positive, the velocity of the system after the collision, v, will be less than u. Therefore, the velocity of the system decreases but does not become zero.
Final Answer:
Option B) Decreases but does not become zero.
When two bodies collide, their velocities can change due to the conservation of momentum and energy. In this case, we have a body of mass m1 moving with velocity u colliding with another stationary body of mass m2.
Conservation of Momentum:
According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.
Before the collision:
Momentum of body 1 = m1 * u
Momentum of body 2 = 0 (as it is stationary)
Total momentum before the collision = m1 * u + 0 = m1 * u
After the collision:
Since the bodies get embedded, they move together with a common velocity v.
Total momentum after the collision = (m1 + m2) * v
According to the law of conservation of momentum:
m1 * u = (m1 + m2) * v
Simplifying the equation:
u = (m1 + m2) * v / m1
Conclusion:
From the equation derived above, we can see that the velocity of the system after the collision, v, is dependent on the masses of both bodies and the initial velocity of body 1, u.
Since the mass of the system after the collision, (m1 + m2), is greater than the mass of body 1, m1, and the velocity u is positive, the velocity of the system after the collision, v, will be less than u. Therefore, the velocity of the system decreases but does not become zero.
Final Answer:
Option B) Decreases but does not become zero.
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29. A body of mass m1 is moving with velocity u. It collides with another stationary body of mass m2. They get embedded. At the point of collision, the velocity of the system :a)increasesb)decreases but does not become zeroc)remains same d)zeroCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 29. A body of mass m1 is moving with velocity u. It collides with another stationary body of mass m2. They get embedded. At the point of collision, the velocity of the system :a)increasesb)decreases but does not become zeroc)remains same d)zeroCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 29. A body of mass m1 is moving with velocity u. It collides with another stationary body of mass m2. They get embedded. At the point of collision, the velocity of the system :a)increasesb)decreases but does not become zeroc)remains same d)zeroCorrect answer is option 'B'. Can you explain this answer?.
29. A body of mass m1 is moving with velocity u. It collides with another stationary body of mass m2. They get embedded. At the point of collision, the velocity of the system :a)increasesb)decreases but does not become zeroc)remains same d)zeroCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 29. A body of mass m1 is moving with velocity u. It collides with another stationary body of mass m2. They get embedded. At the point of collision, the velocity of the system :a)increasesb)decreases but does not become zeroc)remains same d)zeroCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 29. A body of mass m1 is moving with velocity u. It collides with another stationary body of mass m2. They get embedded. At the point of collision, the velocity of the system :a)increasesb)decreases but does not become zeroc)remains same d)zeroCorrect answer is option 'B'. Can you explain this answer?.
Solutions for 29. A body of mass m1 is moving with velocity u. It collides with another stationary body of mass m2. They get embedded. At the point of collision, the velocity of the system :a)increasesb)decreases but does not become zeroc)remains same d)zeroCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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