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N guavas are distributed among 10 boys. The same no. of guavas are distributed among 13 boys. The same exercise is done with 52 boys. What should be the minimum value of N required to distribute, so that no guava is left?
  • a)
    130
  • b)
    520
  • c)
    260
  • d)
    1040
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
N guavas are distributed among 10 boys. The same no. of guavas are dis...
The minimum no. of guavas required is the LCM of 10, 13 and 52.
10 = 2 × 5
13 = 1 × 13
52 = 2 × 2 × 13
LCM of 10, 13 and 52 = 2 × 13 × 2 × 5 = 260
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N guavas are distributed among 10 boys. The same no. of guavas are dis...
Problem:
N guavas are distributed among 10 boys. The same number of guavas are distributed among 13 boys. The same exercise is done with 52 boys. What should be the minimum value of N required to distribute, so that no guava is left?

Solution:
Let's solve this problem step by step:

Step 1: Find the common factors of the given numbers (10, 13, and 52).
- The common factors of 10, 13, and 52 are 1 and 2.

Step 2: Find the lowest common multiple (LCM) of the given numbers.
- The LCM of 10, 13, and 52 is 260.

Step 3: Determine the minimum value of N required to distribute, so that no guava is left.
- The minimum value of N is equal to the LCM, which is 260.

Therefore, the correct answer is option C) 260.
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N guavas are distributed among 10 boys. The same no. of guavas are distributed among 13 boys. The same exercise is done with 52 boys. What should be the minimum value of N required to distribute, so that no guava is left?a)130b)520c)260d)1040Correct answer is option 'C'. Can you explain this answer?
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