A and B can do a piece of work in 30 days, while B and C can do the sa...
2(A + B + C)'s 1 day's work
Therefore, (A + B + C)'s 1 day's work
Work done by A, B, C in 10 days
Now, 1/48 work is done by A in 1 day..
So, 3/8 work will be done by A in
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A and B can do a piece of work in 30 days, while B and C can do the sa...
Given information:
- A and B can do a piece of work in 30 days.
- B and C can do the same work in 24 days.
- C and A can do the same work in 20 days.
- They all work together for 10 days when B and C leave.
To solve this problem, we need to find the individual work rates of A, B, and C, and then determine how long it will take for A to finish the remaining work on their own.
1. Work rates of A, B, and C:
Let's assume that the work done by A in one day is A, by B is B, and by C is C.
From the given information, we can set up the following equations:
1/A + 1/B = 1/30 ---(Equation 1)
1/B + 1/C = 1/24 ---(Equation 2)
1/C + 1/A = 1/20 ---(Equation 3)
2. Solving the equations:
To solve these equations, we can use the method of substitution or elimination. Here, we will use the method of substitution.
From Equation 1, we can express 1/A in terms of B: 1/A = 1/30 - 1/B
Substituting this into Equation 3, we get: 1/C + (1/30 - 1/B) = 1/20
Simplifying the equation, we get: 1/C - 1/B = 1/20 - 1/30
1/C - 1/B = 1/60 ---(Equation 4)
Similarly, we can eliminate A from Equation 2 by substituting 1/A in terms of B:
1/B + 1/C = 1/24
1/B + (1/30 - 1/B) = 1/24
Simplifying the equation, we get: 1/30 + 1/C = 1/24
1/C = 1/24 - 1/30
1/C = 1/120 ---(Equation 5)
Now, we have two equations (Equation 4 and Equation 5) with two variables (B and C). We can solve these equations to find the values of B and C.
Solving Equation 4 and Equation 5, we get:
1/C - 1/B = 1/60 ---(Equation 4)
1/C = 1/120 ---(Equation 5)
Substituting the value of 1/C from Equation 5 into Equation 4, we get:
1/120 - 1/B = 1/60
1/B = 1/60 + 1/120
1/B = 3/120
1/B = 1/40
Therefore, B can complete the work in 40 days.
Substituting the value of B into Equation 1, we can find the value of A:
1/A + 1/40 = 1/30
1/A = 1/30 - 1/40
1/A = 2/120
1/A = 1/60
Therefore, A can complete the work in 60 days.
3. Work done in 10 days:
When A, B, and C work