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In a vibrating system a mass of 3 Kg is suspended by a spring of stiffness 1200 N/m and it is subjected to a harmonic exicitation of 20N. If the viscous damper is provided with the damping coefficient of 75 N-s/m, the
amplitude at resonance is...m
amplitude at resonance is...m
(Important - Enter only the numerical value in the answer)
Correct answer is between '0.011,0.015'. Can you explain this answer?
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In a vibrating system a mass of 3Kg is suspended by a spring ofstiffne...
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Solution:
Given,
m = 3 Kg
k = 1200 N/m
F = 20 N
c = 75 N-s/m
At resonance,
ω = √(k/m) = √(1200/3) = 20 rad/s
Amplitude at resonance can be calculated using the formula,
X = F / [(k - mω^2)2 + c^2ω^2]^(1/2)
Substituting the values, we get
X = 20 / [(1200 - 3(20)^2)^2 + (75)^2(20)^2]^(1/2)
X = 0.013 m
Therefore, the amplitude at resonance is 0.013 m.
Given,
m = 3 Kg
k = 1200 N/m
F = 20 N
c = 75 N-s/m
At resonance,
ω = √(k/m) = √(1200/3) = 20 rad/s
Amplitude at resonance can be calculated using the formula,
X = F / [(k - mω^2)2 + c^2ω^2]^(1/2)
Substituting the values, we get
X = 20 / [(1200 - 3(20)^2)^2 + (75)^2(20)^2]^(1/2)
X = 0.013 m
Therefore, the amplitude at resonance is 0.013 m.
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In a vibrating system a mass of 3Kg is suspended by a spring ofstiffness 1200 N/m and it issubjected to a harmonic exicitationof 20N. If the viscous damper isprovided with the dampingcoefficient of 75 N-s/m, theamplitude at resonance is...m(Important - Enter only the numerical value in the answer)Correct answer is between '0.011,0.015'. Can you explain this answer?
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