Chemistry Exam  >  Chemistry Questions  >  Methyl ketone may be prepared from:a)Carboxyl... Start Learning for Free
Methyl ketone may be prepared from:           
  • a)
    Carboxylic acids, by addition of two equivalents CH3Li           
  • b)
    Acid chlorides, via (CH3)2CuLi addition          
  • c)
    Terminals alkenes, using the wacker process.           
  • d)
    Oxymercuration Demercuration of terminal alkynes.
Correct answer is option 'A,B,C,D'. Can you explain this answer?
Most Upvoted Answer
Methyl ketone may be prepared from:a)Carboxylic acids, by addition of ...
Introduction:
Methyl ketone, also known as methyl ketone, is an organic compound with the formula RC(O)CH3, where R represents an alkyl group. It is commonly used in various industries as a solvent, reagent, or intermediate compound. There are several methods for preparing methyl ketones, and the correct answer includes all of the viable options.

Methods for preparing methyl ketone:

a) Carboxylic acids, by addition of two equivalents CH3Li:
- Methyl ketones can be prepared by reacting carboxylic acids with two equivalents of CH3Li (methyl lithium).
- The reaction begins with the deprotonation of the carboxylic acid by CH3Li, forming a carboxylate anion.
- The carboxylate anion then undergoes nucleophilic addition to the electrophilic carbon of another carboxylic acid molecule, resulting in the formation of a dimer.
- The dimer is then treated with acid, causing it to undergo acid-catalyzed decarboxylation, leading to the formation of the methyl ketone.

b) Acid chlorides, via (CH3)2CuLi addition:
- Acid chlorides can be reacted with (CH3)2CuLi (dimethylcopper lithium) to form methyl ketones.
- The (CH3)2CuLi reagent acts as a nucleophile and attacks the electrophilic carbon of the acid chloride, resulting in the formation of an intermediate.
- The intermediate then undergoes hydrolysis, where it is treated with water or an aqueous acid solution.
- The hydrolysis reaction leads to the formation of the desired methyl ketone.

c) Terminal alkenes, using the Wacker process:
- The Wacker process is a catalytic oxidation reaction that can be used to convert terminal alkenes into methyl ketones.
- The reaction involves the use of a palladium catalyst, a copper salt, and an oxidant such as air or oxygen.
- The palladium catalyst facilitates the oxidative addition of the alkene to the metal center, forming a Pd-alkyl intermediate.
- The intermediate then undergoes migratory insertion, where the alkyl group migrates to the palladium center, resulting in the formation of a Pd-alkyl complex.
- The complex is then oxidized by the copper salt and the oxidant, leading to the formation of the methyl ketone.

d) Oxymercuration-Demercuration of terminal alkynes:
- Terminal alkynes can be converted into methyl ketones through the oxymercuration-demercuration reaction.
- In the oxymercuration step, the terminal alkyne is reacted with mercuric acetate and water, resulting in the formation of a mercurinium ion intermediate.
- The mercurinium ion is then attacked by a nucleophile, such as water, to form a ketone-mercury complex.
- In the demercuration step, the ketone-mercury complex is treated with a reducing agent, such as sodium borohydride, to remove the mercury atom and produce the desired methyl ketone.

Conclusion:
Methyl ketones can be prepared from carboxylic acids, acid chlorides, terminal alkenes, and terminal alk
Explore Courses for Chemistry exam
Methyl ketone may be prepared from:a)Carboxylic acids, by addition of two equivalents CH3Lib)Acid chlorides, via (CH3)2CuLi additionc)Terminals alkenes, using the wacker process.d)Oxymercuration Demercuration of terminal alkynes.Correct answer is option 'A,B,C,D'. Can you explain this answer?
Question Description
Methyl ketone may be prepared from:a)Carboxylic acids, by addition of two equivalents CH3Lib)Acid chlorides, via (CH3)2CuLi additionc)Terminals alkenes, using the wacker process.d)Oxymercuration Demercuration of terminal alkynes.Correct answer is option 'A,B,C,D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Methyl ketone may be prepared from:a)Carboxylic acids, by addition of two equivalents CH3Lib)Acid chlorides, via (CH3)2CuLi additionc)Terminals alkenes, using the wacker process.d)Oxymercuration Demercuration of terminal alkynes.Correct answer is option 'A,B,C,D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Methyl ketone may be prepared from:a)Carboxylic acids, by addition of two equivalents CH3Lib)Acid chlorides, via (CH3)2CuLi additionc)Terminals alkenes, using the wacker process.d)Oxymercuration Demercuration of terminal alkynes.Correct answer is option 'A,B,C,D'. Can you explain this answer?.
Solutions for Methyl ketone may be prepared from:a)Carboxylic acids, by addition of two equivalents CH3Lib)Acid chlorides, via (CH3)2CuLi additionc)Terminals alkenes, using the wacker process.d)Oxymercuration Demercuration of terminal alkynes.Correct answer is option 'A,B,C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry. Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of Methyl ketone may be prepared from:a)Carboxylic acids, by addition of two equivalents CH3Lib)Acid chlorides, via (CH3)2CuLi additionc)Terminals alkenes, using the wacker process.d)Oxymercuration Demercuration of terminal alkynes.Correct answer is option 'A,B,C,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Methyl ketone may be prepared from:a)Carboxylic acids, by addition of two equivalents CH3Lib)Acid chlorides, via (CH3)2CuLi additionc)Terminals alkenes, using the wacker process.d)Oxymercuration Demercuration of terminal alkynes.Correct answer is option 'A,B,C,D'. Can you explain this answer?, a detailed solution for Methyl ketone may be prepared from:a)Carboxylic acids, by addition of two equivalents CH3Lib)Acid chlorides, via (CH3)2CuLi additionc)Terminals alkenes, using the wacker process.d)Oxymercuration Demercuration of terminal alkynes.Correct answer is option 'A,B,C,D'. Can you explain this answer? has been provided alongside types of Methyl ketone may be prepared from:a)Carboxylic acids, by addition of two equivalents CH3Lib)Acid chlorides, via (CH3)2CuLi additionc)Terminals alkenes, using the wacker process.d)Oxymercuration Demercuration of terminal alkynes.Correct answer is option 'A,B,C,D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Methyl ketone may be prepared from:a)Carboxylic acids, by addition of two equivalents CH3Lib)Acid chlorides, via (CH3)2CuLi additionc)Terminals alkenes, using the wacker process.d)Oxymercuration Demercuration of terminal alkynes.Correct answer is option 'A,B,C,D'. Can you explain this answer? tests, examples and also practice Chemistry tests.
Explore Courses for Chemistry exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev