The ratio of the sum of the salaries of A and B to the difference of t...
Given:
- The ratio of the sum of A and B's salaries to the difference of their salaries is 11:1.
- The ratio of the sum of B and C's salaries to the difference of their salaries is also 11:1.
- A's salary is the highest and C's salary is the lowest.
- The total of all their salaries is Rs. 1,82,000.
To find: B's salary.
Let's assume the salaries of A, B, and C as A, B, and C respectively.
The first ratio gives us:
(A + B)/(A - B) = 11/1
We can cross multiply to get:
11(A - B) = A + B
Expanding the equation:
11A - 11B = A + B
Combining like terms:
10A = 12B
Dividing both sides by 12:
A = (6/5)B ...(Equation 1)
Similarly, the second ratio gives us:
(B + C)/(B - C) = 11/1
Cross multiplying:
11(B - C) = B + C
Expanding:
11B - 11C = B + C
Combining like terms:
10B = 12C
Dividing both sides by 12:
B = (6/5)C ...(Equation 2)
We know that A is the highest salary and C is the lowest salary. So, A > B > C.
Now, let's find the values of A, B, and C using the given total of all their salaries:
A + B + C = 1,82,000
Substituting the values of A and B from equations 1 and 2:
(6/5)B + B + C = 1,82,000
(11/5)B + C = 1,82,000
Since A is the highest, let's assume A = 5x (where x is a constant).
Substituting A = 5x in equation 1:
5x = (6/5)B
B = (25/6)x
Substituting A = 5x in the total salary equation:
5x + (25/6)x + C = 1,82,000
(30/6)x + (25/6)x + C = 1,82,000
(55/6)x + C = 1,82,000
Since C is the lowest, let's assume C = y (where y is a constant).
Substituting C = y in the total salary equation:
(55/6)x + y = 1,82,000
Now, we have two equations:
(55/6)x + y = 1,82,000 ...(Equation 3)
B = (25/6)x ...(Equation 4)
To find the value of B, we need to solve equations 3 and 4 simultaneously.
From equation 4, we can express x in terms of B:
(25/6)x = B
x = (6/25)B
Substituting this value of x in equation 3:
(55/6)(6/25)B + y = 1,82,000
(55/25)B + y = 1,82,000
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