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PASSAGE-3A tangent PT is drawn to the circle x2 + y2 = 4 at the point. A straight line L, perpendicular to PT is a tangent to the circle (x – 3)2 + y2 = 1. (2012)Q.A common tangent of the two circles isa)x = 4b)y = 2c)d)Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about PASSAGE-3A tangent PT is drawn to the circle x2 + y2 = 4 at the point. A straight line L, perpendicular to PT is a tangent to the circle (x – 3)2 + y2 = 1. (2012)Q.A common tangent of the two circles isa)x = 4b)y = 2c)d)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PASSAGE-3A tangent PT is drawn to the circle x2 + y2 = 4 at the point. A straight line L, perpendicular to PT is a tangent to the circle (x – 3)2 + y2 = 1. (2012)Q.A common tangent of the two circles isa)x = 4b)y = 2c)d)Correct answer is option 'D'. Can you explain this answer?.

Solutions for PASSAGE-3A tangent PT is drawn to the circle x2 + y2 = 4 at the point. A straight line L, perpendicular to PT is a tangent to the circle (x – 3)2 + y2 = 1. (2012)Q.A common tangent of the two circles isa)x = 4b)y = 2c)d)Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of PASSAGE-3A tangent PT is drawn to the circle x2 + y2 = 4 at the point. A straight line L, perpendicular to PT is a tangent to the circle (x – 3)2 + y2 = 1. (2012)Q.A common tangent of the two circles isa)x = 4b)y = 2c)d)Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of PASSAGE-3A tangent PT is drawn to the circle x2 + y2 = 4 at the point. A straight line L, perpendicular to PT is a tangent to the circle (x – 3)2 + y2 = 1. (2012)Q.A common tangent of the two circles isa)x = 4b)y = 2c)d)Correct answer is option 'D'. Can you explain this answer?, a detailed solution for PASSAGE-3A tangent PT is drawn to the circle x2 + y2 = 4 at the point. A straight line L, perpendicular to PT is a tangent to the circle (x – 3)2 + y2 = 1. (2012)Q.A common tangent of the two circles isa)x = 4b)y = 2c)d)Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of PASSAGE-3A tangent PT is drawn to the circle x2 + y2 = 4 at the point. A straight line L, perpendicular to PT is a tangent to the circle (x – 3)2 + y2 = 1. (2012)Q.A common tangent of the two circles isa)x = 4b)y = 2c)d)Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice PASSAGE-3A tangent PT is drawn to the circle x2 + y2 = 4 at the point. A straight line L, perpendicular to PT is a tangent to the circle (x – 3)2 + y2 = 1. (2012)Q.A common tangent of the two circles isa)x = 4b)y = 2c)d)Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.