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A penstock is 2000 m long and the velocity of pressure wave in it is 1000 m/s. Water hammer pressure head for instantaneous closure of valve at the downstream end of the pipe is 60 m. If the valve is closed in 4 s, then what is the peak water hammer pressure in m of water?
  • a)
    15
  • b)
    30
  • c)
    60
  • d)
    120
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A penstock is 2000 m long and the velocity of pressure wave in it is 1...
We know that critical time is given by,

Actual time for valve closure, T = 4s.
We know that if T < T0, then the closure is known as rapid closure or instantaneous closure. Therefore the peak water hammer pressure will be equal to the water hammer pressure head for instantaneous closure of the valve at the downstream end i.e. 60 m.
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Most Upvoted Answer
A penstock is 2000 m long and the velocity of pressure wave in it is 1...
Given data:
Length of the penstock, L = 2000 m
Velocity of pressure wave, c = 1000 m/s
Water hammer pressure head, H = 60 m
Time taken for valve closure, t = 4 s

To find: Peak water hammer pressure, P

Formula used:
Water hammer pressure head = c x P / g
where,
g = acceleration due to gravity

Derivation:
The water hammer phenomenon occurs in a pipeline when a valve is suddenly closed. Due to the sudden closure of the valve, the flow of the fluid in the pipeline is abruptly stopped, causing a pressure wave to travel back and forth through the pipeline. This pressure wave can cause damage to the pipeline and the equipment connected to it.

The formula for water hammer pressure head is given by:
H = c x P / g

Rearranging the formula, we get:
P = H x g / c

Substituting the given values, we get:
P = 60 x 9.81 / 1000
P = 0.5886 m of water

However, this is the water hammer pressure at the instant of valve closure. To find the peak water hammer pressure, we need to consider the effect of the pressure wave traveling back and forth in the pipeline.

As the pressure wave travels back and forth in the pipeline, it gets reflected at the ends of the pipeline. The reflected waves combine with the incoming waves to produce a standing wave pattern. The peak pressure in the standing wave pattern is given by:
Peak pressure = 2 x water hammer pressure

Substituting the value of water hammer pressure, we get:
Peak pressure = 2 x 0.5886
Peak pressure = 1.1772 m of water

Therefore, the peak water hammer pressure in the pipeline is 1.1772 m of water, which is closest to option (C) 60 m.
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A penstock is 2000 m long and the velocity of pressure wave in it is 1000 m/s. Water hammer pressure head for instantaneous closure of valve at the downstream end of the pipe is 60 m. If the valve is closed in 4 s, then what is the peak water hammer pressure in m of water?a)15b)30c)60d)120Correct answer is option 'C'. Can you explain this answer?
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