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A Pitot-static tube, with a coefficient of velocity 0.98 is used to measure the velocity of water in a pipe. The stagnation pressure recorded is 3 m and the static pressure is 0.5 m. What is the velocity of flow?
  • a)
    7.2 m/s
  • b)
    6.8 m/s
  • c)
    5.9 m/s
  • d)
    5.2 m/s
Correct answer is option 'B'. Can you explain this answer?
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A Pitot-static tube, with a coefficient of velocity 0.98 is used to me...
Given parameters:
Coefficient of velocity (Cv) = 0.98
Stagnation pressure (Ps) = 3 m
Static pressure (P) = 0.5 m

Formula:
Using the Bernoulli’s equation, we can find the velocity of flow using the following formula:
v = √((2*(Ps - P))/ρ)
Where,
v = Velocity of flow
Ps = Stagnation pressure
P = Static pressure
ρ = Density of fluid

Calculation:
Substituting the given values in the formula, we get:
v = √((2*(3 - 0.5))/1000) [Considering density of water as 1000 kg/m³]
v = √((2*2.5)/1000)
v = √0.005
v = 0.0707 m/s

Since the given coefficient of velocity is less than 1, we need to multiply the calculated velocity by the coefficient of velocity to get the actual velocity. Therefore,
Actual velocity (V) = Cv * v
V = 0.98 * 0.0707
V = 0.0693 m/s

Rounding off the answer to one decimal place, we get
V ≈ 6.8 m/s

Therefore, the velocity of flow is 6.8 m/s (option B).
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A Pitot-static tube, with a coefficient of velocity 0.98 is used to measure the velocity of water in a pipe. The stagnation pressure recorded is 3 m and the static pressure is 0.5 m. What is the velocity of flow?a)7.2 m/sb)6.8 m/sc)5.9 m/sd)5.2 m/sCorrect answer is option 'B'. Can you explain this answer?
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