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A wattmeter has a current coil of 0.1 Ω resistance and a pressure coil of 6500 Ω respectively. The wattmeter shows a reading of 12 A at 250 V with unity power factor. The percentage errors, due to resistance only with each of the two methods of connections shown below will be respectively
  • a)
    0.26% in connection (i) and 0.16% in connection (ii)
  • b)
    0.32% in connection (i) and 0.48% in connection (ii)
  • c)
    0.16% in connection (i) and 0.26% in connection (ii)
  • d)
    0.48% in connection (i) and 0.32% in connection (a)
Correct answer is option 'D'. Can you explain this answer?
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Ohms resistance and a voltage coil of 100 ohms resistance. The current coil is connected in series with the load and the voltage coil is connected in parallel with the load. The current through the load is 10 A and the voltage across the load is 100 V.

To calculate the power consumed by the load using the wattmeter, we need to calculate the total resistance of the circuit.

The resistance of the current coil is given as 0.1 ohms, and the resistance of the voltage coil is given as 100 ohms.

In series connection, the total resistance is the sum of the resistance of the load and the current coil, which is 0.1 ohms + load resistance.

In parallel connection, the total resistance is given by the reciprocal of the sum of the reciprocals of the load resistance and the voltage coil resistance.

Let's assume the load resistance is R ohms.

So, the total resistance in series connection is 0.1 + R ohms.

The total resistance in parallel connection is 1 / (1/R + 1/100) ohms.

Since the current coil is connected in series with the load, the current passing through the circuit is 10 A.

Using Ohm's Law, V = I * R, we can calculate the voltage across the load.

So, V = 10 * R volts.

Now, using the power formula, P = V * I, we can calculate the power consumed by the load.

P = (10 * R) * 10

P = 100 * R watts.

Since the wattmeter is connected in parallel with the load, it measures the power accurately.

Therefore, the power consumed by the load can be directly read from the wattmeter as 100 * R watts.
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A wattmeter has a current coil of 0.1 Ω resistance and a pressure coil of 6500 Ω respectively. The wattmeter shows a reading of 12 A at 250 V with unity power factor.The percentage errors, due to resistance only with each of the two methods of connections shown below will be respectivelya)0.26% in connection (i) and 0.16% in connection (ii)b)0.32% in connection (i) and 0.48% in connection (ii)c)0.16% in connection (i) and 0.26% in connection (ii)d)0.48% in connection (i) and 0.32% in connection (a)Correct answer is option 'D'. Can you explain this answer?
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A wattmeter has a current coil of 0.1 Ω resistance and a pressure coil of 6500 Ω respectively. The wattmeter shows a reading of 12 A at 250 V with unity power factor.The percentage errors, due to resistance only with each of the two methods of connections shown below will be respectivelya)0.26% in connection (i) and 0.16% in connection (ii)b)0.32% in connection (i) and 0.48% in connection (ii)c)0.16% in connection (i) and 0.26% in connection (ii)d)0.48% in connection (i) and 0.32% in connection (a)Correct answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A wattmeter has a current coil of 0.1 Ω resistance and a pressure coil of 6500 Ω respectively. The wattmeter shows a reading of 12 A at 250 V with unity power factor.The percentage errors, due to resistance only with each of the two methods of connections shown below will be respectivelya)0.26% in connection (i) and 0.16% in connection (ii)b)0.32% in connection (i) and 0.48% in connection (ii)c)0.16% in connection (i) and 0.26% in connection (ii)d)0.48% in connection (i) and 0.32% in connection (a)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wattmeter has a current coil of 0.1 Ω resistance and a pressure coil of 6500 Ω respectively. The wattmeter shows a reading of 12 A at 250 V with unity power factor.The percentage errors, due to resistance only with each of the two methods of connections shown below will be respectivelya)0.26% in connection (i) and 0.16% in connection (ii)b)0.32% in connection (i) and 0.48% in connection (ii)c)0.16% in connection (i) and 0.26% in connection (ii)d)0.48% in connection (i) and 0.32% in connection (a)Correct answer is option 'D'. Can you explain this answer?.
Solutions for A wattmeter has a current coil of 0.1 Ω resistance and a pressure coil of 6500 Ω respectively. The wattmeter shows a reading of 12 A at 250 V with unity power factor.The percentage errors, due to resistance only with each of the two methods of connections shown below will be respectivelya)0.26% in connection (i) and 0.16% in connection (ii)b)0.32% in connection (i) and 0.48% in connection (ii)c)0.16% in connection (i) and 0.26% in connection (ii)d)0.48% in connection (i) and 0.32% in connection (a)Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
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