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Direction (Q. Nos. 1-12) This section contains 12 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.
Q. Which of the following compounds are soluble in H2O ?
- a)CH3CHO
- b)CH3COCH3
- c)CH3CH2OH
- d)All of these
Correct answer is option 'D'. Can you explain this answer?
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Direction (Q. Nos. 1-12) This section contains 12 multiple choice ques...
All these are soluble in water due to intermolecular H-bonding.
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Direction (Q. Nos. 1-12) This section contains 12 multiple choice ques...
Solubility in Water
Water is a polar molecule, meaning it has a slight positive charge at one end and a slight negative charge at the other end. This polarity allows water molecules to form hydrogen bonds with other polar molecules or ions, making them soluble in water. On the other hand, nonpolar molecules do not form hydrogen bonds with water and are generally insoluble.
In the given options, we need to determine which compounds are soluble in water.
Explanation of options:
a) CH3CHO (acetaldehyde)
- Acetaldehyde is a polar molecule due to the presence of the carbonyl group (C=O) and the difference in electronegativity between carbon and oxygen atoms.
- The polar nature of acetaldehyde allows it to form hydrogen bonds with water molecules, making it soluble in water.
b) CH3COCH3 (acetone)
- Acetone is a polar molecule due to the presence of the carbonyl group (C=O) and the difference in electronegativity between carbon and oxygen atoms.
- The polar nature of acetone allows it to form hydrogen bonds with water molecules, making it soluble in water.
c) CH3CH2OH (ethanol)
- Ethanol is a polar molecule due to the presence of the hydroxyl group (OH) and the difference in electronegativity between carbon, oxygen, and hydrogen atoms.
- The polar nature of ethanol allows it to form hydrogen bonds with water molecules, making it soluble in water.
d) All of these
- This option is correct because all the given compounds (acetaldehyde, acetone, and ethanol) are soluble in water due to their polar nature and ability to form hydrogen bonds with water molecules.
Therefore, the correct answer is option 'd) All of these'.
Water is a polar molecule, meaning it has a slight positive charge at one end and a slight negative charge at the other end. This polarity allows water molecules to form hydrogen bonds with other polar molecules or ions, making them soluble in water. On the other hand, nonpolar molecules do not form hydrogen bonds with water and are generally insoluble.
In the given options, we need to determine which compounds are soluble in water.
Explanation of options:
a) CH3CHO (acetaldehyde)
- Acetaldehyde is a polar molecule due to the presence of the carbonyl group (C=O) and the difference in electronegativity between carbon and oxygen atoms.
- The polar nature of acetaldehyde allows it to form hydrogen bonds with water molecules, making it soluble in water.
b) CH3COCH3 (acetone)
- Acetone is a polar molecule due to the presence of the carbonyl group (C=O) and the difference in electronegativity between carbon and oxygen atoms.
- The polar nature of acetone allows it to form hydrogen bonds with water molecules, making it soluble in water.
c) CH3CH2OH (ethanol)
- Ethanol is a polar molecule due to the presence of the hydroxyl group (OH) and the difference in electronegativity between carbon, oxygen, and hydrogen atoms.
- The polar nature of ethanol allows it to form hydrogen bonds with water molecules, making it soluble in water.
d) All of these
- This option is correct because all the given compounds (acetaldehyde, acetone, and ethanol) are soluble in water due to their polar nature and ability to form hydrogen bonds with water molecules.
Therefore, the correct answer is option 'd) All of these'.
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Direction (Q. Nos. 1-12) This section contains 12 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.Q.Which of the following compounds are soluble in H2O?a)CH3CHOb)CH3COCH3c)CH3CH2OHd)All of theseCorrect answer is option 'D'. Can you explain this answer?
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