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Minimum of the real valued function f(x) = (x-1)2/3 occurs at  x equal to
  • a)
    - ∝
  • b)
    0
  • c)
    1
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Minimum of the real valued function f(x) = (x-1)2/3 occurs at x equal ...

As f(x) is square of hence its minimum value be 0 where at x = 1.
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Most Upvoted Answer
Minimum of the real valued function f(x) = (x-1)2/3 occurs at x equal ...
In cuberoot -ve value can be, so in cube root value should equal to zero or more  .
minimum is zero x-1=0, x=1 will be answer
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Community Answer
Minimum of the real valued function f(x) = (x-1)2/3 occurs at x equal ...
We can see we have (x-1)² ie f(x) can never be negative Hence min value is 0 at x = 1
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Minimum of the real valued function f(x) = (x-1)2/3 occurs at x equal toa)- ∝b)0c)1d)∝Correct answer is option 'C'. Can you explain this answer?
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