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A single-phase transistorized bridge inverter has a resistive load of R = 3 Ω and the dc input voltage of 48 volts. The total harmonic distortion is approximately equal to
  • a)
    28.80%
  • b)
    23.33%
  • c)
    42.62%
  • d)
    48.43%
Correct answer is option 'D'. Can you explain this answer?
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The output voltage of a single-phase transistorized bridge inverter with a resistive load can be calculated using the following formula:

V_out = (2 * V_dc) / π * sin(ω * t)

Where:
- V_out is the output voltage
- V_dc is the DC input voltage
- ω is the angular frequency of the AC output waveform
- t is the time

The resistive load has a resistance of R = 3.

To calculate the output voltage, we need to know the values of V_dc, ω, and t.
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A single-phase transistorized bridge inverter has a resistive load of R = 3 Ω and the dc input voltage of 48 volts. The total harmonic distortion is approximately equal toa)28.80%b)23.33%c)42.62%d)48.43%Correct answer is option 'D'. Can you explain this answer?
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