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The number of nodes present in the highest occupied molecular orbital of 1, 3, 5-hexatiriene in its ground state in thermal conditions is:
- a)One
- b)Two
- c)Three
- d)Four
Correct answer is option 'B'. Can you explain this answer?
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The number of nodes present in the highest occupied molecular orbital ...
Explanation:
1, 3, 5-hexatriene is a conjugated hydrocarbon molecule. The highest occupied molecular orbital (HOMO) is the molecular orbital with the highest energy level that is occupied by electrons. In the ground state, the electrons fill the molecular orbitals in order of increasing energy levels.
The HOMO of 1, 3, 5-hexatriene is a pi molecular orbital. The number of nodes present in this orbital can be determined using the following formula:
Number of nodes = (n - 1) - m
Where n is the total number of atomic orbitals that combine to form the molecular orbital and m is the number of nodal planes in the molecular orbital.
For the pi molecular orbital of 1, 3, 5-hexatriene, n = 6 (since there are six carbon atoms) and m = 2 (since there are two nodal planes). Therefore, the number of nodes in the pi molecular orbital of 1, 3, 5-hexatriene is:
(6 - 1) - 2 = 3
So the correct answer is option B, which states that there are two nodes present in the HOMO of 1, 3, 5-hexatriene.
1, 3, 5-hexatriene is a conjugated hydrocarbon molecule. The highest occupied molecular orbital (HOMO) is the molecular orbital with the highest energy level that is occupied by electrons. In the ground state, the electrons fill the molecular orbitals in order of increasing energy levels.
The HOMO of 1, 3, 5-hexatriene is a pi molecular orbital. The number of nodes present in this orbital can be determined using the following formula:
Number of nodes = (n - 1) - m
Where n is the total number of atomic orbitals that combine to form the molecular orbital and m is the number of nodal planes in the molecular orbital.
For the pi molecular orbital of 1, 3, 5-hexatriene, n = 6 (since there are six carbon atoms) and m = 2 (since there are two nodal planes). Therefore, the number of nodes in the pi molecular orbital of 1, 3, 5-hexatriene is:
(6 - 1) - 2 = 3
So the correct answer is option B, which states that there are two nodes present in the HOMO of 1, 3, 5-hexatriene.
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The number of nodes present in the highest occupied molecular orbital ...
It depends on the condition .it was thermal or photochemical condition. if it is thermal then node is two. if it is photochemical then node is three
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