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Four particles lie initially at the corners of a square of side length L. All the particles start to move with speed v. A moves towards B, B moves towards C, C moves towards D and D moves towards A. The distance covered by a particle till they meet, is?
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Four particles lie initially at the corners of a square of side length...
Solution:
The particles move along the diagonal of the square towards each other. Let's assume they meet at the center of the square.
Step 1: Find the distance between two opposite corners of the square.
The distance between two opposite corners of the square is the diagonal of the square. Using the Pythagorean theorem, we can find the diagonal of the square as:
d = sqrt(2L^2)
Step 2: Find the time taken by the particles to reach the center of the square.
Each particle is moving towards the center of the square with a speed of v. The distance it needs to cover is d/2 (the distance from its starting point to the center of the square). Therefore, the time taken by each particle to reach the center of the square is:
t = (d/2) / v = (sqrt(2)L/2) / v
Step 3: Find the distance covered by each particle till they meet.
Since all particles are moving towards the center of the square with the same speed, they cover equal distances in the same amount of time. Therefore, the distance covered by each particle till they meet is:
distance = v*t = v*(sqrt(2)L/2) / v = (sqrt(2)L/2)
Hence, the distance covered by each particle till they meet is (sqrt(2)L/2).
The particles move along the diagonal of the square towards each other. Let's assume they meet at the center of the square.
Step 1: Find the distance between two opposite corners of the square.
The distance between two opposite corners of the square is the diagonal of the square. Using the Pythagorean theorem, we can find the diagonal of the square as:
d = sqrt(2L^2)
Step 2: Find the time taken by the particles to reach the center of the square.
Each particle is moving towards the center of the square with a speed of v. The distance it needs to cover is d/2 (the distance from its starting point to the center of the square). Therefore, the time taken by each particle to reach the center of the square is:
t = (d/2) / v = (sqrt(2)L/2) / v
Step 3: Find the distance covered by each particle till they meet.
Since all particles are moving towards the center of the square with the same speed, they cover equal distances in the same amount of time. Therefore, the distance covered by each particle till they meet is:
distance = v*t = v*(sqrt(2)L/2) / v = (sqrt(2)L/2)
Hence, the distance covered by each particle till they meet is (sqrt(2)L/2).
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Four particles lie initially at the corners of a square of side length...
Tajmahal banwaya tha shah jahan ne mumtaj ke liye or aaj bhi hm kuware baithe sirf apke liye
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Four particles lie initially at the corners of a square of side length L. All the particles start to move with speed v. A moves towards B, B moves towards C, C moves towards D and D moves towards A. The distance covered by a particle till they meet, is?
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Four particles lie initially at the corners of a square of side length L. All the particles start to move with speed v. A moves towards B, B moves towards C, C moves towards D and D moves towards A. The distance covered by a particle till they meet, is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Four particles lie initially at the corners of a square of side length L. All the particles start to move with speed v. A moves towards B, B moves towards C, C moves towards D and D moves towards A. The distance covered by a particle till they meet, is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Four particles lie initially at the corners of a square of side length L. All the particles start to move with speed v. A moves towards B, B moves towards C, C moves towards D and D moves towards A. The distance covered by a particle till they meet, is?.
Four particles lie initially at the corners of a square of side length L. All the particles start to move with speed v. A moves towards B, B moves towards C, C moves towards D and D moves towards A. The distance covered by a particle till they meet, is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Four particles lie initially at the corners of a square of side length L. All the particles start to move with speed v. A moves towards B, B moves towards C, C moves towards D and D moves towards A. The distance covered by a particle till they meet, is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Four particles lie initially at the corners of a square of side length L. All the particles start to move with speed v. A moves towards B, B moves towards C, C moves towards D and D moves towards A. The distance covered by a particle till they meet, is?.
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