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a block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. initially the system is at rest when a particle of mass m falls on the pan and sticks to it. if the particle strike the pan with a speed v. find the speed with which the system moves just after the collision
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a block of mass m and a pan of equal mass are connected by a string go...
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a block of mass m and a pan of equal mass are connected by a string go...
Problem:
A block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. Initially, the system is at rest when a particle of mass m falls on the pan and sticks to it. If the particle strikes the pan with a speed v, find the speed with which the system moves just after the collision.
Solution:
1. Understanding the Problem:
We have a system consisting of a block and a pan connected by a string. The block has mass m and the pan also has mass m. Initially, the system is at rest. A particle of mass m falls onto the pan and sticks to it, striking the pan with a speed v. We need to find the speed with which the system moves just after the collision.
2. Analyzing the System:
Let's analyze the system components and their properties:
- Block mass: m
- Pan mass: m
- Particle mass: m
- Initial speed of the particle: v
- Final speed of the system: ?
3. Applying Conservation of Momentum:
To solve this problem, we can apply the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
4. Calculating Initial Momentum:
Before the collision, the system is at rest, so the initial momentum is zero.
Initial momentum = 0
5. Calculating Final Momentum:
After the collision, the particle of mass m sticks to the pan, and both move together. Let's assume the final speed of the system is V.
Final momentum = (Total mass of the system) * (Final speed of the system)
Final momentum = (2m) * V
6. Applying Conservation of Momentum:
According to the principle of conservation of momentum:
Initial momentum = Final momentum
0 = (2m) * V
Therefore, V = 0
7. Conclusion:
The speed with which the system moves just after the collision is zero. Since the particle sticks to the pan, the system remains at rest after the collision.
A block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. Initially, the system is at rest when a particle of mass m falls on the pan and sticks to it. If the particle strikes the pan with a speed v, find the speed with which the system moves just after the collision.
Solution:
1. Understanding the Problem:
We have a system consisting of a block and a pan connected by a string. The block has mass m and the pan also has mass m. Initially, the system is at rest. A particle of mass m falls onto the pan and sticks to it, striking the pan with a speed v. We need to find the speed with which the system moves just after the collision.
2. Analyzing the System:
Let's analyze the system components and their properties:
- Block mass: m
- Pan mass: m
- Particle mass: m
- Initial speed of the particle: v
- Final speed of the system: ?
3. Applying Conservation of Momentum:
To solve this problem, we can apply the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
4. Calculating Initial Momentum:
Before the collision, the system is at rest, so the initial momentum is zero.
Initial momentum = 0
5. Calculating Final Momentum:
After the collision, the particle of mass m sticks to the pan, and both move together. Let's assume the final speed of the system is V.
Final momentum = (Total mass of the system) * (Final speed of the system)
Final momentum = (2m) * V
6. Applying Conservation of Momentum:
According to the principle of conservation of momentum:
Initial momentum = Final momentum
0 = (2m) * V
Therefore, V = 0
7. Conclusion:
The speed with which the system moves just after the collision is zero. Since the particle sticks to the pan, the system remains at rest after the collision.
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a block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. initially the system is at rest when a particle of mass m falls on the pan and sticks to it. if the particle strike the pan with a speed v. find the speed with which the system moves just after the collision Related: Centre of Mass - System of Particles and Rotational Motion, Class 11, Physics
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a block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. initially the system is at rest when a particle of mass m falls on the pan and sticks to it. if the particle strike the pan with a speed v. find the speed with which the system moves just after the collision Related: Centre of Mass - System of Particles and Rotational Motion, Class 11, Physics for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about a block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. initially the system is at rest when a particle of mass m falls on the pan and sticks to it. if the particle strike the pan with a speed v. find the speed with which the system moves just after the collision Related: Centre of Mass - System of Particles and Rotational Motion, Class 11, Physics covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. initially the system is at rest when a particle of mass m falls on the pan and sticks to it. if the particle strike the pan with a speed v. find the speed with which the system moves just after the collision Related: Centre of Mass - System of Particles and Rotational Motion, Class 11, Physics.
a block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. initially the system is at rest when a particle of mass m falls on the pan and sticks to it. if the particle strike the pan with a speed v. find the speed with which the system moves just after the collision Related: Centre of Mass - System of Particles and Rotational Motion, Class 11, Physics for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about a block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. initially the system is at rest when a particle of mass m falls on the pan and sticks to it. if the particle strike the pan with a speed v. find the speed with which the system moves just after the collision Related: Centre of Mass - System of Particles and Rotational Motion, Class 11, Physics covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. initially the system is at rest when a particle of mass m falls on the pan and sticks to it. if the particle strike the pan with a speed v. find the speed with which the system moves just after the collision Related: Centre of Mass - System of Particles and Rotational Motion, Class 11, Physics.
Solutions for a block of mass m and a pan of equal mass are connected by a string going over a smooth light pulley. initially the system is at rest when a particle of mass m falls on the pan and sticks to it. if the particle strike the pan with a speed v. find the speed with which the system moves just after the collision Related: Centre of Mass - System of Particles and Rotational Motion, Class 11, Physics in English & in Hindi are available as part of our courses for Class 11.
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