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then g(x) has
  • a)
    local maxima at x = 1 + ln 2 and local minima at x = e
  • b)
    local maxima at x = 1 and local minima at x = 2
  • c)
    no local maxima
  • d)
    no local minima
Correct answer is option 'A,B'. Can you explain this answer?
Verified Answer
then g(x) hasa)local maxima at x = 1 + ln 2 and local minima at x = e...



∴ g ''(1 + ln 2) =-2 and g ''(e) = 1⇒ g (x) has local max. at x = 1 + ln 2 and local min. at x = e.

Also graph of g '(x) suggests, g (x) has local max. at x = 1 and local min. at x = 2
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Most Upvoted Answer
then g(x) hasa)local maxima at x = 1 + ln 2 and local minima at x = e...
Correct is A and B
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then g(x) hasa)local maxima at x = 1 + ln 2 and local minima at x = eb)local maxima at x = 1 and local minima at x = 2c)no local maximad)no local minimaCorrect answer is option 'A,B'. Can you explain this answer?
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