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A closed tank containing water to a depth of 1.5 m falls vertically with an acceleration of 2 m/s2. What is the pressure at the bottom of the tank?
- a)12.5 kN/m2
- b)13.3 kN/m2
- c)11.7 kN/m2
- d)10.5 kN/m2
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A closed tank containing water to a depth of 1.5 m falls vertically wi...
Pressure at bottom of tank
= p (g - a) h = 1000 x (9.81 - 2) x 1.5
= 11.7 kN/m2
= p (g - a) h = 1000 x (9.81 - 2) x 1.5
= 11.7 kN/m2
Most Upvoted Answer
A closed tank containing water to a depth of 1.5 m falls vertically wi...
To find the pressure at the bottom of the tank, we can use the concept of hydrostatic pressure. Hydrostatic pressure is the pressure exerted by a fluid at rest due to the weight of the fluid above it.
We can determine the pressure at the bottom of the tank using the formula:
P = ρgh
Where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid column. In this case, the fluid is water and its density is approximately 1000 kg/m3. The acceleration due to gravity, g, is 9.8 m/s2.
Given that the tank falls vertically with an acceleration of 2 m/s2 and the depth of the water is 1.5 m, we need to consider the net acceleration acting on the water. The net acceleration is the sum of the acceleration due to gravity and the acceleration of the tank. In this case, the net acceleration is 9.8 m/s2 + 2 m/s2 = 11.8 m/s2.
Now, we can substitute the values into the formula:
P = 1000 kg/m3 * 11.8 m/s2 * 1.5 m
P = 17,700 N/m2
To convert the pressure from N/m2 to kN/m2, we divide by 1000:
P = 17,700 N/m2 / 1000 = 17.7 kN/m2
Therefore, the pressure at the bottom of the tank is 17.7 kN/m2.
We can determine the pressure at the bottom of the tank using the formula:
P = ρgh
Where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid column. In this case, the fluid is water and its density is approximately 1000 kg/m3. The acceleration due to gravity, g, is 9.8 m/s2.
Given that the tank falls vertically with an acceleration of 2 m/s2 and the depth of the water is 1.5 m, we need to consider the net acceleration acting on the water. The net acceleration is the sum of the acceleration due to gravity and the acceleration of the tank. In this case, the net acceleration is 9.8 m/s2 + 2 m/s2 = 11.8 m/s2.
Now, we can substitute the values into the formula:
P = 1000 kg/m3 * 11.8 m/s2 * 1.5 m
P = 17,700 N/m2
To convert the pressure from N/m2 to kN/m2, we divide by 1000:
P = 17,700 N/m2 / 1000 = 17.7 kN/m2
Therefore, the pressure at the bottom of the tank is 17.7 kN/m2.
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Community Answer
A closed tank containing water to a depth of 1.5 m falls vertically wi...
Closed tank 2m x 2m x6m high and weighing 1500 N has a hole in one side of the wall with
effective area of 8cm2
and situated 190 mm above the tank bottom. The tank is filled with
water to a depth of 3 m. Determine the air pressure in the tank that is required to set it into
motion if the coefficient of friction between ground and wheel is 0.015
effective area of 8cm2
and situated 190 mm above the tank bottom. The tank is filled with
water to a depth of 3 m. Determine the air pressure in the tank that is required to set it into
motion if the coefficient of friction between ground and wheel is 0.015
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A closed tank containing water to a depth of 1.5 m falls vertically with an acceleration of 2 m/s2. What is the pressure at the bottom of the tank?a)12.5 kN/m2b)13.3 kN/m2c)11.7 kN/m2d)10.5 kN/m2Correct answer is option 'C'. Can you explain this answer?
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