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Let S be the surface of cone z=√x^2 y^2 bounded by the planes z=0 and z=3. further, let C be the closed curve forming the boundary of the surface S. A vector field F is such that curl F =-xi-yj .the absolute value of the line integral F.dr?
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Let S be the surface of cone z=√x^2 y^2 bounded by the planes z=0 and ...
The Surface S and the Closed Curve C

The surface S is a cone that is bounded by the planes z=0 and z=3. The equation of the cone is z=√(x^2 + y^2). This means that for any point (x, y, z) on the cone, the z-coordinate is equal to the square root of the sum of the squares of the x and y coordinates.

The closed curve C forms the boundary of the surface S. It is the intersection of the cone with the planes z=0 and z=3. The curve C is a circle in the xy-plane with radius 3, centered at the origin (0, 0, 0).

The Vector Field F and its Curl

The vector field F is given by F = -x i - y j, where i and j are the standard unit vectors in the x and y directions, respectively. The curl of F, denoted as curl F, is a vector field that measures the rotation or circulation of F.

The curl of F can be calculated using the formula: curl F = (∂Fz/∂y - ∂Fy/∂z) i + (∂Fx/∂z - ∂Fz/∂x) j + (∂Fy/∂x - ∂Fx/∂y) k, where i, j, and k are the standard unit vectors in the x, y, and z directions, respectively.

In this case, F = -x i - y j, so ∂Fz/∂y = 0, ∂Fy/∂z = 0, ∂Fx/∂z = 0, ∂Fz/∂x = 0, ∂Fy/∂x = -1, and ∂Fx/∂y = -1. Therefore, curl F = -1 k.

The Line Integral of F along the Closed Curve C

The line integral of a vector field F along a closed curve C can be calculated using the formula: ∮ F · dr, where dr is a differential vector along the curve C.

In this case, we need to calculate the line integral of F along the closed curve C that forms the boundary of the surface S. Since the surface S is a cone, the curve C is a circle in the xy-plane with radius 3, centered at the origin (0, 0, 0).

Since the vector field F = -x i - y j, we can write F · dr = (-x i - y j) · (dx i + dy j). Simplifying this expression, we get F · dr = -x dx - y dy.

To calculate the line integral, we need to parameterize the curve C. Let's use polar coordinates. Let r(t) = 3 cos(t) i + 3 sin(t) j, where t ranges from 0 to 2π.

Now, dr = (dx/dt) dt i + (dy/dt) dt j. Since x = 3 cos(t) and y = 3 sin(t), we have dx/dt = -3 sin(t) and dy/dt = 3 cos(t).

Substituting these values into F · dr = -x dx - y dy, we
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Let S be the surface of cone z=√x^2 y^2 bounded by the planes z=0 and ...
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Let S be the surface of cone z=√x^2 y^2 bounded by the planes z=0 and z=3. further, let C be the closed curve forming the boundary of the surface S. A vector field F is such that curl F =-xi-yj .the absolute value of the line integral F.dr?
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Let S be the surface of cone z=√x^2 y^2 bounded by the planes z=0 and z=3. further, let C be the closed curve forming the boundary of the surface S. A vector field F is such that curl F =-xi-yj .the absolute value of the line integral F.dr? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about Let S be the surface of cone z=√x^2 y^2 bounded by the planes z=0 and z=3. further, let C be the closed curve forming the boundary of the surface S. A vector field F is such that curl F =-xi-yj .the absolute value of the line integral F.dr? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let S be the surface of cone z=√x^2 y^2 bounded by the planes z=0 and z=3. further, let C be the closed curve forming the boundary of the surface S. A vector field F is such that curl F =-xi-yj .the absolute value of the line integral F.dr?.
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