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A real gas is subjected to an adiabatic process from ( 2 bar, 40L, 300K) to (4 bar, 30L , 300K) against a constant pressure of 4 bar. The enthalpy change for the process in kJ is ?
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A real gas is subjected to an adiabatic process from ( 2 bar, 40L, 300...
Given data:
Initial state:
Pressure (P1) = 2 bar
Volume (V1) = 40L
Temperature (T1) = 300K
Final state:
Pressure (P2) = 4 bar
Volume (V2) = 30L
Temperature (T2) = 300K
Constant pressure during the process: 4 bar
Adiabatic process:
An adiabatic process is a thermodynamic process in which there is no transfer of heat between the system and its surroundings. In other words, the process is insulated and no heat is gained or lost.
Enthalpy change:
Enthalpy change (ΔH) is the heat transferred to or from a system at constant pressure. In an adiabatic process, there is no heat transfer, so the enthalpy change is zero (ΔH = 0).
Calculation:
To determine the enthalpy change, we need to calculate the work done during the process.
1. Calculate the work done:
The work done (W) during an adiabatic process can be calculated using the formula:
W = P2 * V2 - P1 * V1
Substituting the given values:
W = (4 bar) * (30L) - (2 bar) * (40L)
W = 120 bar.L - 80 bar.L
W = 40 bar.L
Note: 1 bar.L = 100 J
So, W = 40 bar.L * 100 J/bar.L
W = 4000 J
2. Calculate the enthalpy change:
Since the process is adiabatic, ΔH = 0.
Hence, the enthalpy change for the process is zero (0 kJ).
Initial state:
Pressure (P1) = 2 bar
Volume (V1) = 40L
Temperature (T1) = 300K
Final state:
Pressure (P2) = 4 bar
Volume (V2) = 30L
Temperature (T2) = 300K
Constant pressure during the process: 4 bar
Adiabatic process:
An adiabatic process is a thermodynamic process in which there is no transfer of heat between the system and its surroundings. In other words, the process is insulated and no heat is gained or lost.
Enthalpy change:
Enthalpy change (ΔH) is the heat transferred to or from a system at constant pressure. In an adiabatic process, there is no heat transfer, so the enthalpy change is zero (ΔH = 0).
Calculation:
To determine the enthalpy change, we need to calculate the work done during the process.
1. Calculate the work done:
The work done (W) during an adiabatic process can be calculated using the formula:
W = P2 * V2 - P1 * V1
Substituting the given values:
W = (4 bar) * (30L) - (2 bar) * (40L)
W = 120 bar.L - 80 bar.L
W = 40 bar.L
Note: 1 bar.L = 100 J
So, W = 40 bar.L * 100 J/bar.L
W = 4000 J
2. Calculate the enthalpy change:
Since the process is adiabatic, ΔH = 0.
Hence, the enthalpy change for the process is zero (0 kJ).
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A real gas is subjected to an adiabatic process from ( 2 bar, 40L, 300K) to (4 bar, 30L , 300K) against a constant pressure of 4 bar. The enthalpy change for the process in kJ is ? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A real gas is subjected to an adiabatic process from ( 2 bar, 40L, 300K) to (4 bar, 30L , 300K) against a constant pressure of 4 bar. The enthalpy change for the process in kJ is ? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A real gas is subjected to an adiabatic process from ( 2 bar, 40L, 300K) to (4 bar, 30L , 300K) against a constant pressure of 4 bar. The enthalpy change for the process in kJ is ?.
A real gas is subjected to an adiabatic process from ( 2 bar, 40L, 300K) to (4 bar, 30L , 300K) against a constant pressure of 4 bar. The enthalpy change for the process in kJ is ? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A real gas is subjected to an adiabatic process from ( 2 bar, 40L, 300K) to (4 bar, 30L , 300K) against a constant pressure of 4 bar. The enthalpy change for the process in kJ is ? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A real gas is subjected to an adiabatic process from ( 2 bar, 40L, 300K) to (4 bar, 30L , 300K) against a constant pressure of 4 bar. The enthalpy change for the process in kJ is ?.
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