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If the observed staff reading at a station is 800.925 m the correction due to refraction is 0.115 m and correction due to curvature is 0.805. Then the correct staff reading will be
  • a)
    801.615 m
  • b)
    800.235 m
  • c)
    800.005 m
  • d)
    800.120 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If the observed staff reading at a station is 800.925 m the correction...
True staff reading = obs. staff reading - curve corr. + refr. corr.
= 800.925 -0.805 + 0.115 
= 800.235 m
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Most Upvoted Answer
If the observed staff reading at a station is 800.925 m the correction...
Given Data:
Observed staff reading at a station = 800.925 m
Correction due to refraction = 0.115 m
Correction due to curvature = 0.805 m

To find: Correct staff reading

Solution:
The correct staff reading is obtained by subtracting the correction due to refraction and correction due to curvature from the observed staff reading at a station.

Correct staff reading = Observed staff reading - Correction due to refraction - Correction due to curvature
= 800.925 - 0.115 - 0.805
= 800.005 m

Therefore, the correct staff reading is 800.005 m, which is option (b).
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If the observed staff reading at a station is 800.925 m the correction due to refraction is 0.115 m and correction due to curvature is 0.805. Then the correct staff reading will bea)801.615 mb)800.235 mc)800.005 md)800.120 mCorrect answer is option 'B'. Can you explain this answer?
Question Description
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