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Let ω be a complex cube root of unity with ω ≠ 1 and P = [pij] be a n × n matrix with pij = ωi+j. Then p2 ≠ 0, when n =a)57b)55c)58d)56Correct answer is option 'B,C,D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let ω be a complex cube root of unity with ω ≠ 1 and P = [pij] be a n × n matrix with pij = ωi+j. Then p2 ≠ 0, when n =a)57b)55c)58d)56Correct answer is option 'B,C,D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let ω be a complex cube root of unity with ω ≠ 1 and P = [pij] be a n × n matrix with pij = ωi+j. Then p2 ≠ 0, when n =a)57b)55c)58d)56Correct answer is option 'B,C,D'. Can you explain this answer?.

Solutions for Let ω be a complex cube root of unity with ω ≠ 1 and P = [pij] be a n × n matrix with pij = ωi+j. Then p2 ≠ 0, when n =a)57b)55c)58d)56Correct answer is option 'B,C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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