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If fore bearing of a line is S49°52'E (assuming there is no local attraction), the back bearing of the line will be
  • a)
    S52°49'E    
  • b)
    S49°52'E
  • c)
    N49°08'E    
  • d)
    N49°52'W
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If fore bearing of a line is S49°52'E (assuming there is no lo...
if the fore bearing of a line is given as the quadrantal bearing, then back bearing is numerically equal to the fore bearing. However N changes to S and Exchanges to W and vice versa.
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Most Upvoted Answer
If fore bearing of a line is S49°52'E (assuming there is no lo...
It means that the line is oriented towards the south-southeast direction, with an angle of 49 degrees measured clockwise from the true north direction.
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If fore bearing of a line is S49°52'E (assuming there is no local attraction), the back bearing of the line will bea)S52°49'E b)S49°52'Ec)N49°08'E d)N49°52'WCorrect answer is option 'D'. Can you explain this answer?
Question Description
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