Two pipes A and B can fill a tank in 20 hours and 25 hours respectivel...
To solve this problem, we can use the concept of work. Let's assume that the capacity of the tank is 100 units (this is an arbitrary value and does not affect the final answer).
Let's calculate the work done by each pipe in 1 hour:
- Pipe A can fill 100/20 = 5 units per hour.
- Pipe B can fill 100/25 = 4 units per hour.
- Pipe C can empty 100/50 = 2 units per hour.
Now, let's calculate the work done by all three pipes together in 1 hour:
- Pipes A and B together can fill 5 + 4 = 9 units per hour.
- When pipe C is also open, the net work done by all three pipes is 9 - 2 = 7 units per hour (since pipe C is emptying the tank).
We are given that the total time to fill the tank is 13 hours. So, in 13 hours, the total work done by all three pipes is 13 * 7 = 91 units.
Now, let's find out how much work was done by pipe C alone before it was closed. Since the total work done by all three pipes is 91 units and the work done by pipes A and B together is 9 units per hour, the work done by pipe C alone is 91 - 9 = 82 units.
Since pipe C can empty 2 units per hour, the time taken for pipe C to empty 82 units is 82 / 2 = 41 hours.
However, we need to find out after how much time pipe C was closed, not how long it took to empty the tank completely. Since the total time to fill the tank is 13 hours, and pipe C was open for 41 hours, the time after which pipe C was closed is 41 - 13 = 28 hours.
Therefore, the correct answer is option 'C', after 28 hours pipe C was closed.