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Let ∑μn be a series of positive terms. Given that ∑μn is convergent and also  exists, then the said limit is
  • a)
    necessarily equal to -1
  • b)
    necessarily greater than -1
  • c)
    may be equal to 1 or less than 1
  • d)
    necessarily less than 1
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Let ∑μnbe a series of positive terms. Given that ∑μn is ...

unique quantity.
Then, from Eq. (i) we have 
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Let ∑μnbe a series of positive terms. Given that ∑μn is convergent and also exists, then the saidlimit isa)necessarily equal to -1b)necessarily greater than -1c)may be equal to 1 or less than 1d)necessarily less than 1Correct answer is option 'D'. Can you explain this answer?
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Let ∑μnbe a series of positive terms. Given that ∑μn is convergent and also exists, then the saidlimit isa)necessarily equal to -1b)necessarily greater than -1c)may be equal to 1 or less than 1d)necessarily less than 1Correct answer is option 'D'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about Let ∑μnbe a series of positive terms. Given that ∑μn is convergent and also exists, then the saidlimit isa)necessarily equal to -1b)necessarily greater than -1c)may be equal to 1 or less than 1d)necessarily less than 1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let ∑μnbe a series of positive terms. Given that ∑μn is convergent and also exists, then the saidlimit isa)necessarily equal to -1b)necessarily greater than -1c)may be equal to 1 or less than 1d)necessarily less than 1Correct answer is option 'D'. Can you explain this answer?.
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