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The equation of the straight line which makes an angle of 135° with the positive direction of the a--axis and cuts off an intercept equal to 5 on y-axis is given by
  • a)
    y+x-5-0
  • b)
    y=x+5
  • c)
    y=1/2x+5
  • d)
    y=5
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The equation of the straight line which makes an angle of 135° wit...
Note that the equation of a straight line which makes an angle 0 with the positive direction of the x-axis and cuts an intercept equal to c on y-axis, is given by

y= mx + c,
where m = tan θ.
In this problem,
c = 5
and
θ= 135° ⇒ w = tan 135° = -1 Required equation is given by
y = -x+5 
or y + x = 5
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Most Upvoted Answer
The equation of the straight line which makes an angle of 135° wit...
Note that the equation of a straight line which makes an angle 0 with the positive direction of the x-axis and cuts an intercept equal to c on y-axis, is given by

y= mx + c,
where m = tan θ.
In this problem,
c = 5
and
θ= 135° ⇒ w = tan 135° = -1 Required equation is given by
y = -x+5 
or y + x = 5
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The equation of the straight line which makes an angle of 135° with the positive direction of the a--axis and cuts off an intercept equal to 5 on y-axis is given bya)y+x-5-0b)y=x+5c)y=1/2x+5d)y=5Correct answer is option 'A'. Can you explain this answer?
Question Description
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