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Consider the following procedure declaration:
procedure p ;
x : integer;
procedure q;
begin x = x + 1 end;
procedure r;
x : integer;
begin x := 1; q ; write(x) end;
begin
x = 2;
r;
end;
The output produced by calling Pin a language with dynamic scope will be
  • a)
    1
  • b)
    2
  • c)
    3
  • d)
    4
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Consider the following procedure declaration:procedure p ;x : integer;...
Since value output by program is the value of x which is declared in side DC function, so, output is 1 using dynamic scoping.
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Most Upvoted Answer
Consider the following procedure declaration:procedure p ;x : integer;...
Explanation:

Procedure p:
- The procedure p sets the value of x to 2 and then calls procedure r.

Procedure r:
- Inside procedure r, x is set to 1.
- Then procedure q is called.
- Inside procedure q, x is incremented by 1, making x equal to 2.
- Finally, the value of x (which is now 2) is written to the output.

Therefore, the output produced by calling procedure p will be 1.
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