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If half adders and full adders are implemented using gates, then for the addition of two 17 bit numbers (using minimum gates) the number of half adders and full adders required will be
- a)0,17
- b)16,1
- c)1 , 1 6
- d)8 , 8
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
If half adders and full adders are implemented using gates, then for t...
As we know that n bit full adder circuit can represent (n + 1) bits sum. In order to represent addition of two 17 bits numbers we require minimum of 16 full adder and 1 half adder.
Note: For the first bit we can use either HA or FA. Hence, for addition of two 17 bit numbers inspire of 17 full adders we can perform the same task using 16 FA and 1 HA.
Hence (c) is the correct option.
Note: For the first bit we can use either HA or FA. Hence, for addition of two 17 bit numbers inspire of 17 full adders we can perform the same task using 16 FA and 1 HA.
Hence (c) is the correct option.
Most Upvoted Answer
If half adders and full adders are implemented using gates, then for t...
Understanding Half Adders and Full Adders
Half adders and full adders are basic building blocks in digital electronics for binary addition.
- Half Adder: It adds two single-bit binary numbers and produces a sum and a carry. It requires:
- 1 XOR gate for the sum
- 1 AND gate for the carry
- Full Adder: It adds three single-bit binary numbers (two significant bits and a carry from the previous addition). It consists of:
- 2 XOR gates for the sum
- 2 AND gates and 1 OR gate for the carry
Adding Two 17-Bit Numbers
To add two 17-bit binary numbers, we need to consider how many bits must be added and how to manage carries.
- Most Significant Bit (MSB) Addition:
- The addition of the two MSBs requires a full adder, since there is no carry-in at this stage.
- Subsequent Bit Additions:
- The next 16 bits can be handled using full adders where each full adder takes the carry from the previous addition.
Gate Configuration for 17-Bit Addition
- Full Adders:
- 1 full adder for the MSB
- 16 full adders for the subsequent bits
- Half Adders:
- Only one half adder is needed for the very first addition to generate the initial sum without a carry.
Final Count of Adders
- Total Required:
- Half Adders: 1
- Full Adders: 16
Thus, when adding two 17-bit numbers, the configuration requires 1 half adder and 16 full adders, leading to the correct answer being option 'C'.
Half adders and full adders are basic building blocks in digital electronics for binary addition.
- Half Adder: It adds two single-bit binary numbers and produces a sum and a carry. It requires:
- 1 XOR gate for the sum
- 1 AND gate for the carry
- Full Adder: It adds three single-bit binary numbers (two significant bits and a carry from the previous addition). It consists of:
- 2 XOR gates for the sum
- 2 AND gates and 1 OR gate for the carry
Adding Two 17-Bit Numbers
To add two 17-bit binary numbers, we need to consider how many bits must be added and how to manage carries.
- Most Significant Bit (MSB) Addition:
- The addition of the two MSBs requires a full adder, since there is no carry-in at this stage.
- Subsequent Bit Additions:
- The next 16 bits can be handled using full adders where each full adder takes the carry from the previous addition.
Gate Configuration for 17-Bit Addition
- Full Adders:
- 1 full adder for the MSB
- 16 full adders for the subsequent bits
- Half Adders:
- Only one half adder is needed for the very first addition to generate the initial sum without a carry.
Final Count of Adders
- Total Required:
- Half Adders: 1
- Full Adders: 16
Thus, when adding two 17-bit numbers, the configuration requires 1 half adder and 16 full adders, leading to the correct answer being option 'C'.
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If half adders and full adders are implemented using gates, then for the addition of two 17 bit numbers (using minimum gates) the number of half adders and full adders required will bea)0,17b)16,1c)1 , 1 6d)8 , 8Correct answer is option 'C'. Can you explain this answer?
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If half adders and full adders are implemented using gates, then for the addition of two 17 bit numbers (using minimum gates) the number of half adders and full adders required will bea)0,17b)16,1c)1 , 1 6d)8 , 8Correct answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about If half adders and full adders are implemented using gates, then for the addition of two 17 bit numbers (using minimum gates) the number of half adders and full adders required will bea)0,17b)16,1c)1 , 1 6d)8 , 8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If half adders and full adders are implemented using gates, then for the addition of two 17 bit numbers (using minimum gates) the number of half adders and full adders required will bea)0,17b)16,1c)1 , 1 6d)8 , 8Correct answer is option 'C'. Can you explain this answer?.
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