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A rectangular channel is 6 m wide and discharges 30 m3s-1. The upstream depth is 2.0 m, acceleration due to gravity is 10 ms-2. Then, what is the specific energy (approximate)?
  • a)
    2.5
  • b)
    0.3
  • c)
    2.3
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A rectangular channel is 6 m wide and discharges 30 m3s-1. The upstrea...
We know that, 
Q = AV

⇒  \/ = 2.5 m/s
The specific energy may be given as,
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Most Upvoted Answer
A rectangular channel is 6 m wide and discharges 30 m3s-1. The upstrea...
Given data:
Width of the rectangular channel (B) = 6 m
Discharge (Q) = 30 m3/s
Upstream depth (y1) = 2.0 m
Acceleration due to gravity (g) = 10 m/s2

Specific energy (E) can be calculated using the following formula:
E = y + Q2/2gA2

Where,
y = Depth of flow at a point (m)
A = Cross-sectional area of flow (m2)

Calculation:
The cross-sectional area of flow (A) can be calculated as:
A = By1
A = 6 × 2
A = 12 m2

Velocity of flow (V) can be calculated as:
V = Q/A
V = 30/12
V = 2.5 m/s

Specific energy (E) can be calculated as:
E = y1 + (Q2/2gA2)
E = 2.0 + [(30)2/2 × 10 × (12)2]
E = 2.3 m

Therefore, the specific energy of the rectangular channel is 2.3 m (approximate). Hence, option (C) is the correct answer.
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