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A blocks is moved from rest through a distance of 4m along a straight line path. The mass of the blocks is 5 kg. and the force acting on it is 20 N . If the kinetic energy acquired by the block be 40J, at what angle to the path the force is acting-
- a)30º
- b)60º
- c)45º
- d)none of the above
Correct answer is option 'B'. Can you explain this answer?
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To find the angle at which the force is acting, we can use the formula for work:
Work = Force * Distance * cos(angle)
Given that the work done is 40 J, the force is 20 N, and the distance is 4 m, we can rearrange the formula to solve for the angle:
40 J = 20 N * 4 m * cos(angle)
Dividing both sides by (20 N * 4 m) gives:
40 J / (20 N * 4 m) = cos(angle)
Simplifying:
1 J / (2 N * m) = cos(angle)
Now, we can take the inverse cosine (cos^(-1)) of both sides to find the angle:
cos^(-1)(1 J / (2 N * m)) = angle
Using a calculator, we find:
angle ≈ 60.80 degrees (rounded to two decimal places)
Therefore, the angle at which the force is acting is approximately 60.80 degrees.
Work = Force * Distance * cos(angle)
Given that the work done is 40 J, the force is 20 N, and the distance is 4 m, we can rearrange the formula to solve for the angle:
40 J = 20 N * 4 m * cos(angle)
Dividing both sides by (20 N * 4 m) gives:
40 J / (20 N * 4 m) = cos(angle)
Simplifying:
1 J / (2 N * m) = cos(angle)
Now, we can take the inverse cosine (cos^(-1)) of both sides to find the angle:
cos^(-1)(1 J / (2 N * m)) = angle
Using a calculator, we find:
angle ≈ 60.80 degrees (rounded to two decimal places)
Therefore, the angle at which the force is acting is approximately 60.80 degrees.
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A blocks is moved from rest through a distance of 4m along a straight line path. The mass of the blocks is 5 kg. and the force acting on it is 20 N . If the kinetic energy acquired by the block be 40J, at what angle to the path the force is acting-a)30ºb)60ºc)45ºd)none of the aboveCorrect answer is option 'B'. Can you explain this answer?
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