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A 20 kg box is pulled up on a slope with a constant speed to a distance of 4 maths raising it to a height of 2 mts above its starting point, the force F that exerted on the box?
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A 20 kg box is pulled up on a slope with a constant speed to a distanc...
Calculating the Force Exerted on a Box


Given:


  • Mass of the box (m) = 20 kg

  • Distance traveled along the slope (d) = 4 m

  • Height gained (h) = 2 m

  • Speed of the box (v) = constant



Formula:

The force exerted on the box can be calculated using the formula:

F = mg(sinθ + μcosθ)

where,

  • m = mass of the box

  • g = acceleration due to gravity (9.8 m/s²)

  • θ = angle of the slope with the horizontal

  • μ = coefficient of friction between the box and the slope



Calculations:

Given,

  • m = 20 kg

  • d = 4 m

  • h = 2 m



To calculate θ, we can use the formula:

sinθ = h/d

sinθ = 2/4

sinθ = 0.5

θ = sin⁻¹(0.5)

θ ≈ 30°

Assuming that the coefficient of friction between the box and the slope is negligible (μ = 0), the force exerted on the box can be calculated as:

F = mg(sinθ)

F = 20 x 9.8 x 0.5

F = 98 N

Therefore, the force exerted on the box is 98 N.
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A 20 kg box is pulled up on a slope with a constant speed to a distanc...
What is the time required?
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