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Let A = 1111 1010 and B = 0000 1010 be two 8-bit 2’s complement numbers. Their product in 2’s complement is
  • a)
    1100 0100
  • b)
    1001 1100
  • c)
    10100101
  • d)
    11010101
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Let A = 1111 1010 and B = 0000 1010 be two 8-bit 2’s complement ...
A = 11111010
Since MSB is 1 hence number is negative i.e. - (00000110)
= -(00000110)
A = - 6
B = 00001010,
There is number 2’s complement representation for positive number B = +10 
A x B = 10 x (- 6)
= - 60
Binary representation of - 60 = 00111100 
Now take 2’s complement = 11000100
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Most Upvoted Answer
Let A = 1111 1010 and B = 0000 1010 be two 8-bit 2’s complement ...
's complement binary numbers. To find the sum of A and B, we can add them together using binary addition:

1111 1010
+ 0000 1010
-----------
1 0000 0100

The sum of A and B is 10000 0100.
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Let A = 1111 1010 and B = 0000 1010 be two 8-bit 2’s complement numbers. Their product in 2’s complement isa)1100 0100b)1001 1100c)10100101d)11010101Correct answer is option 'A'. Can you explain this answer?
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