Civil Engineering (CE) Exam  >  Civil Engineering (CE) Questions  >  If the velocity is zero over half of the cros... Start Learning for Free
If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor is
  • a)
    1
  • b)
    4/3
  • c)
    2
  • d)
    4
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If the velocity is zero over half of the cross- sectionai area and is ...
Momentum correction factor,

View all questions of this test
Most Upvoted Answer
If the velocity is zero over half of the cross- sectionai area and is ...
Momentum Correction Factor for Flow in Pipes with Variable Velocity Profile

Introduction:
Momentum correction factor is defined as the ratio of the actual force exerted on a fluid by the pipe wall to the force that would be exerted on the fluid if the velocity profile were uniform across the pipe cross-section.

Given Information:
In this question, the velocity is zero over half of the cross-sectional area and is uniform over the remaining half.

Calculation:
Momentum correction factor is given by the formula:

ΔP_actual = fρLV^2/2D

ΔP_ideal = ρV^2/2

f = (ΔP_actual/ΔP_ideal) * (D/L)

where
ΔP_actual is the actual pressure drop in the pipe
ΔP_ideal is the pressure drop for a fluid with uniform velocity profile
f is the friction factor
ρ is the density of the fluid
L is the length of the pipe
D is the diameter of the pipe
V is the average velocity of the fluid

For a pipe with variable velocity profile, the friction factor is given by the equation:

f = (1/2) * [ln⁡(1 + 2Re_L^0.5 cosh^-1 (y_max/D)) - ln⁡(1 + 2Re_L^0.5 cosh^-1 (y_min/D))]

where
Re = ρVD/μ is the Reynolds number
μ is the dynamic viscosity of the fluid
y_max is the maximum distance from the centerline of the pipe to the fluid velocity profile
y_min is the minimum distance from the centerline of the pipe to the fluid velocity profile

In this question, the velocity is zero over half of the cross-sectional area and is uniform over the remaining half. Therefore, y_max = D/2 and y_min = 0.

Substituting the values in the equation, we get:

f = (1/2) * [ln⁡(1 + 2Re_L^0.5 cosh^-1 (1)) - ln⁡(1 + 2Re_L^0.5 cosh^-1 (0))]

f = (1/2) * [ln⁡(1 + 2Re_L^0.5) - ln(1)]

f = (1/2) * ln⁡(1 + 2Re_L^0.5)

The momentum correction factor is given by:

C_f = (1 + f/2) / (1 - f/6)

Substituting the value of f, we get:

C_f = (1 + (1/2)ln⁡(1 + 2Re_L^0.5)) / (1 - (1/12)ln⁡(1 + 2Re_L^0.5))

Conclusion:
Therefore, the momentum correction factor for the given flow condition is 2 (option C).
Explore Courses for Civil Engineering (CE) exam

Top Courses for Civil Engineering (CE)

If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor isa)1b)4/3c)2d)4Correct answer is option 'C'. Can you explain this answer?
Question Description
If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor isa)1b)4/3c)2d)4Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor isa)1b)4/3c)2d)4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor isa)1b)4/3c)2d)4Correct answer is option 'C'. Can you explain this answer?.
Solutions for If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor isa)1b)4/3c)2d)4Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor isa)1b)4/3c)2d)4Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor isa)1b)4/3c)2d)4Correct answer is option 'C'. Can you explain this answer?, a detailed solution for If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor isa)1b)4/3c)2d)4Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor isa)1b)4/3c)2d)4Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor isa)1b)4/3c)2d)4Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
Explore Courses for Civil Engineering (CE) exam

Top Courses for Civil Engineering (CE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev