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If at 298 K the bond energies of C—H, C—C, C=C and H—H are, respectively, 414, 347, 615 and 435 kJ mol–1, the value of enthalpy change for the reaction CH2=CH2(g) + H2(g) → H3C—CH3(g) at 298 K will be:           
  • a)
    +250 kJ                       
  • b)
    –250 kJ                          
  • c)
    +125 kJ                    
  • d)
    –125 kJ
Correct answer is option 'D'. Can you explain this answer?
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If at 298 K the bond energies of C—H, C—C, C=C and H&mdash...
The bond energies of C-C, C-H, and C-O bonds at 298 K are as follows:

- C-C bond energy: 347 kJ/mol
- C-H bond energy: 413 kJ/mol
- C-O bond energy: 358 kJ/mol
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If at 298 K the bond energies of C—H, C—C, C=C and H&mdash...
And will be c not d...
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If at 298 K the bond energies of C—H, C—C, C=C and H—H are, respectively, 414, 347, 615 and 435 kJ mol–1, the value of enthalpy change for the reaction CH2=CH2(g) + H2(g) → H3C—CH3(g) at 298 K will be:a)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer?
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If at 298 K the bond energies of C—H, C—C, C=C and H—H are, respectively, 414, 347, 615 and 435 kJ mol–1, the value of enthalpy change for the reaction CH2=CH2(g) + H2(g) → H3C—CH3(g) at 298 K will be:a)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about If at 298 K the bond energies of C—H, C—C, C=C and H—H are, respectively, 414, 347, 615 and 435 kJ mol–1, the value of enthalpy change for the reaction CH2=CH2(g) + H2(g) → H3C—CH3(g) at 298 K will be:a)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If at 298 K the bond energies of C—H, C—C, C=C and H—H are, respectively, 414, 347, 615 and 435 kJ mol–1, the value of enthalpy change for the reaction CH2=CH2(g) + H2(g) → H3C—CH3(g) at 298 K will be:a)+250 kJb)–250 kJc)+125 kJd)–125 kJCorrect answer is option 'D'. Can you explain this answer?.
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