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For the reaction, N2(g) + 3H2(g)→ 2NH3(g)​Compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.a)ΔS° = –37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.b)ΔS° = –198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.c)ΔS° = –31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.d)ΔS° = –31.25 J/K/mol; positive sign indicates that the reaction is spontaneousCorrect answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about For the reaction, N2(g) + 3H2(g)→ 2NH3(g)​Compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.a)ΔS° = –37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.b)ΔS° = –198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.c)ΔS° = –31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.d)ΔS° = –31.25 J/K/mol; positive sign indicates that the reaction is spontaneousCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the reaction, N2(g) + 3H2(g)→ 2NH3(g)​Compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.a)ΔS° = –37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.b)ΔS° = –198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.c)ΔS° = –31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.d)ΔS° = –31.25 J/K/mol; positive sign indicates that the reaction is spontaneousCorrect answer is option 'B'. Can you explain this answer?.

Solutions for For the reaction, N2(g) + 3H2(g)→ 2NH3(g)​Compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.a)ΔS° = –37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.b)ΔS° = –198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.c)ΔS° = –31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.d)ΔS° = –31.25 J/K/mol; positive sign indicates that the reaction is spontaneousCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry. Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.

Here you can find the meaning of For the reaction, N2(g) + 3H2(g)→ 2NH3(g)​Compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.a)ΔS° = –37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.b)ΔS° = –198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.c)ΔS° = –31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.d)ΔS° = –31.25 J/K/mol; positive sign indicates that the reaction is spontaneousCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of For the reaction, N2(g) + 3H2(g)→ 2NH3(g)​Compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.a)ΔS° = –37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.b)ΔS° = –198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.c)ΔS° = –31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.d)ΔS° = –31.25 J/K/mol; positive sign indicates that the reaction is spontaneousCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for For the reaction, N2(g) + 3H2(g)→ 2NH3(g)​Compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.a)ΔS° = –37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.b)ΔS° = –198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.c)ΔS° = –31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.d)ΔS° = –31.25 J/K/mol; positive sign indicates that the reaction is spontaneousCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of For the reaction, N2(g) + 3H2(g)→ 2NH3(g)​Compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.a)ΔS° = –37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.b)ΔS° = –198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.c)ΔS° = –31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.d)ΔS° = –31.25 J/K/mol; positive sign indicates that the reaction is spontaneousCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice For the reaction, N2(g) + 3H2(g)→ 2NH3(g)​Compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.a)ΔS° = –37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.b)ΔS° = –198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.c)ΔS° = –31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction.d)ΔS° = –31.25 J/K/mol; positive sign indicates that the reaction is spontaneousCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Chemistry tests.