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Among the species O2, O2-, O22-, O2+ their respective bond order values are w, x, y and z respectively. What is the value of w + x + y + z?
    Correct answer is '7'. Can you explain this answer?
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    Among the species O2, O2-, O22-, O2+ their respective bond order value...
    Bond Order in Species O2, O2-, O22-, O2

    The bond order is a measure of the stability of a chemical bond in a molecule. It represents the number of chemical bonds between a pair of atoms. In general, a higher bond order indicates a stronger and more stable bond.

    Species and their respective bond order:
    - O2: ?
    - O2-: ?
    - O22-: ?
    - O2: ?

    To determine the bond order of each species, we need to follow the rules of molecular orbital theory. According to this theory, molecular orbitals are formed by the combination of atomic orbitals. In the case of diatomic molecules, such as O2, the molecular orbitals are formed by the combination of atomic orbitals from each atom (Oxygen in this case).

    Steps to determine bond order:
    1. Write the electron configuration of the molecule.
    2. Determine the number of bonding and antibonding electrons.
    3. Calculate the bond order using the formula: Bond Order = (Number of bonding electrons - Number of antibonding electrons) / 2.

    Bond order for O2:
    1. The electron configuration of oxygen (O) is 1s2 2s2 2p4.
    2. In O2, each oxygen atom contributes 6 electrons (2 from 2p and 4 from 2p) for a total of 12 electrons.
    3. Using the formula, Bond Order = (Number of bonding electrons - Number of antibonding electrons) / 2, we need to determine the number of bonding and antibonding electrons.
    - In O2, there are 10 bonding electrons (5 pairs) and 2 antibonding electrons (1 pair).
    - Bond Order = (10 - 2) / 2 = 4 / 2 = 2.

    Bond order for O2-:
    1. O2- has gained an extra electron compared to O2. This additional electron occupies the antibonding molecular orbital.
    2. The electron configuration of O2- is 1s2 2s2 2p6, with a total of 15 electrons.
    3. Using the formula for bond order, we find:
    - There are 8 bonding electrons (4 pairs) and 6 antibonding electrons (3 pairs).
    - Bond Order = (8 - 6) / 2 = 2 / 2 = 1.

    Bond order for O22-:
    1. O22- has gained two extra electrons compared to O2. These additional electrons occupy the antibonding molecular orbitals.
    2. The electron configuration of O22- is 1s2 2s2 2p6 3s2 3p6, with a total of 18 electrons.
    3. Using the formula for bond order, we find:
    - There are 10 bonding electrons (5 pairs) and 8 antibonding electrons (4 pairs).
    - Bond Order = (10 - 8) / 2 = 2 / 2 = 1.

    Bond order for O2:
    1. O2 has lost two electrons compared to O2-. These lost electrons were in the antibonding molecular orbitals.
    2. The electron configuration of
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    Among the species O2, O2-, O22-, O2+ their respective bond order values are w, x, y and z respectively. What is the value of w + x + y + z?Correct answer is '7'. Can you explain this answer?
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