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A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?
- a)40 bytes
- b)80 bytes
- c)120 bytes
- d)160 bytes
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A TCP message consisting of 2100 bytes is passed to IP for delivery ac...
In the question they have directly given the payload so 2100 will be divided into 1200 and 904 (900 is not a multiple of 8 so we have to pad 4 bits in order to make it a multiple of 8).
Now in second network payload is 400 B.
So 1200 bytes packet will be divided in 400,400, 400 with each having 20 B header, and 900 will be divided into 400,400 and 104 (4 bits padded) each having 20 B header.
So total overhead is 20 x 6 = 120 B.
Now in second network payload is 400 B.
So 1200 bytes packet will be divided in 400,400, 400 with each having 20 B header, and 900 will be divided into 400,400 and 104 (4 bits padded) each having 20 B header.
So total overhead is 20 x 6 = 120 B.
Most Upvoted Answer
A TCP message consisting of 2100 bytes is passed to IP for delivery ac...
Total IP Overhead Calculation
To understand the total IP overhead in the second network, we need to analyze the transmission of the TCP message through both networks.
Step 1: Initial Message Size
- The original TCP message size is 2100 bytes.
Step 2: First Network Characteristics
- Maximum payload per frame: 1200 bytes
- IP overhead per packet: 20 bytes
Step 3: Fragmentation for the First Network
- The first network can carry 1200 bytes of payload per frame.
- After adding the IP overhead, each frame can carry 1200 - 20 = 1180 bytes of TCP data.
- To accommodate 2100 bytes, we need to send:
- 1st frame: 1180 bytes
- 2nd frame: 920 bytes (remaining TCP data)
- Therefore, the first network sends 2 frames.
Step 4: Second Network Characteristics
- Maximum payload per frame: 400 bytes
Step 5: Fragmentation for the Second Network
- Each frame can carry 400 - 20 = 380 bytes of TCP data after the IP overhead.
- The TCP data to be sent from the first network is:
- 1st frame (from first network): 1180 bytes
- 2nd frame (from first network): 920 bytes
- Total data for the second network: 1180 + 920 = 2100 bytes
Step 6: Total Frames Needed in the Second Network
- To send 2100 bytes using 380 bytes per frame, we calculate:
- Number of frames = 2100 / 380 ≈ 6 frames (with the last frame carrying the remainder).
Step 7: Total IP Overhead in the Second Network
- Each frame incurs 20 bytes of IP overhead.
- Total IP overhead = 6 frames * 20 bytes = 120 bytes.
Thus, the total IP overhead for the second network is 120 bytes.
The correct answer is option 'C'.
To understand the total IP overhead in the second network, we need to analyze the transmission of the TCP message through both networks.
Step 1: Initial Message Size
- The original TCP message size is 2100 bytes.
Step 2: First Network Characteristics
- Maximum payload per frame: 1200 bytes
- IP overhead per packet: 20 bytes
Step 3: Fragmentation for the First Network
- The first network can carry 1200 bytes of payload per frame.
- After adding the IP overhead, each frame can carry 1200 - 20 = 1180 bytes of TCP data.
- To accommodate 2100 bytes, we need to send:
- 1st frame: 1180 bytes
- 2nd frame: 920 bytes (remaining TCP data)
- Therefore, the first network sends 2 frames.
Step 4: Second Network Characteristics
- Maximum payload per frame: 400 bytes
Step 5: Fragmentation for the Second Network
- Each frame can carry 400 - 20 = 380 bytes of TCP data after the IP overhead.
- The TCP data to be sent from the first network is:
- 1st frame (from first network): 1180 bytes
- 2nd frame (from first network): 920 bytes
- Total data for the second network: 1180 + 920 = 2100 bytes
Step 6: Total Frames Needed in the Second Network
- To send 2100 bytes using 380 bytes per frame, we calculate:
- Number of frames = 2100 / 380 ≈ 6 frames (with the last frame carrying the remainder).
Step 7: Total IP Overhead in the Second Network
- Each frame incurs 20 bytes of IP overhead.
- Total IP overhead = 6 frames * 20 bytes = 120 bytes.
Thus, the total IP overhead for the second network is 120 bytes.
The correct answer is option 'C'.
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A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?a)40 bytesb)80 bytesc)120 bytesd)160 bytesCorrect answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?a)40 bytesb)80 bytesc)120 bytesd)160 bytesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?a)40 bytesb)80 bytesc)120 bytesd)160 bytesCorrect answer is option 'C'. Can you explain this answer?.
A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?a)40 bytesb)80 bytesc)120 bytesd)160 bytesCorrect answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?a)40 bytesb)80 bytesc)120 bytesd)160 bytesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?a)40 bytesb)80 bytesc)120 bytesd)160 bytesCorrect answer is option 'C'. Can you explain this answer?.
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A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?a)40 bytesb)80 bytesc)120 bytesd)160 bytesCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?a)40 bytesb)80 bytesc)120 bytesd)160 bytesCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?a)40 bytesb)80 bytesc)120 bytesd)160 bytesCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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