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A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?
  • a)
    40 bytes
  • b)
    80 bytes
  • c)
    120 bytes
  • d)
    160 bytes
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A TCP message consisting of 2100 bytes is passed to IP for delivery ac...
In the question they have directly given the payload so 2100 will be divided into 1200 and 904 (900 is not a multiple of 8 so we have to pad 4 bits in order to make it a multiple of 8).
Now in second network payload is 400 B.
So 1200 bytes packet will be divided in 400,400, 400 with each having 20 B header, and 900 will be divided into 400,400 and 104 (4 bits padded) each having 20 B header.
So total overhead is 20 x 6 = 120 B.
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A TCP message consisting of 2100 bytes is passed to IP for delivery across two networks. The first network can carry a maximum payload of 1200 bytes per frame and the second network can carry a maximum payload of 400 bytes per frame, excluding network overhead. Assume that IP overhead per packet is 20 bytes. What is the total IP overhead in the second network for this transmission?a)40 bytesb)80 bytesc)120 bytesd)160 bytesCorrect answer is option 'C'. Can you explain this answer?
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