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Given an IP address 156.233.42.56 with a subnet mask of 7 bits. How many hosts and subnets are possible.
  • a)
    126 hosts and 510 subnets
  • b)
    128 hosts and 512 subnets
  • c)
    510 hosts and 126 subnets
  • d)
    512 hosts and 128 subnets
Correct answer is option 'C'. Can you explain this answer?
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Given an IP address 156.233.42.56 with a subnet mask of 7 bits. How ma...
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Given an IP address 156.233.42.56 with a subnet mask of 7 bits. How ma...
Explanation:
To determine the number of hosts and subnets possible, we first need to determine the number of bits used for the network portion and the host portion of the IP address.

Given IP address 156.233.42.56, the binary representation of the address is:
10011100.11101001.00101010.00111000

With a subnet mask of 7 bits, the network portion of the address is:
1001110 0.1110100 1.0010101 0.0011100

This leaves 25 bits for the host portion of the address.

Number of Subnets
With 7 bits used for the network portion of the address, there are 2^7 (or 128) possible subnets.

Number of Hosts
With 25 bits used for the host portion of the address, there are 2^25 (or 33,554,432) possible hosts per subnet.

Therefore, the correct answer is option C, 510 hosts and 126 subnets.
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Given an IP address 156.233.42.56 with a subnet mask of 7 bits. How many hosts and subnets are possible.a)126 hosts and 510 subnetsb)128 hosts and 512 subnetsc)510 hosts and 126 subnetsd)512 hosts and 128 subnetsCorrect answer is option 'C'. Can you explain this answer?
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