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If 0.32 g of an organic compound containing sulphur produces 0.233g of BaSO₄. Then the percentage of sulphur in it is
  • a)
    10
  • b)
    15
  • c)
    20
  • d)
    25
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If 0.32 g of an organic compound containing sulphur produces 0.233g of...
Given information:
- Mass of organic compound containing sulphur = 0.32 g
- Mass of BaSO4 produced from the combustion of this compound = 0.233 g

To find: Percentage of sulphur in the organic compound

Solution:
1. Write the balanced chemical equation for the combustion of the organic compound containing sulphur in the presence of excess oxygen:

Organic compound containing sulphur + excess O2 → CO2 + H2O + SO2

2. Calculate the number of moles of BaSO4 produced:
- Molar mass of BaSO4 = 233.4 g/mol (atomic masses: Ba = 137.3 g/mol, S = 32.1 g/mol, O = 16.0 g/mol x 4)
- Moles of BaSO4 = mass/molar mass = 0.233/233.4 = 0.001 moles

3. Calculate the number of moles of sulphur in the organic compound:
- From the balanced chemical equation, 1 mole of the organic compound containing sulphur produces 1 mole of SO2
- Moles of SO2 = Moles of BaSO4 = 0.001 moles
- Moles of sulphur = Moles of SO2 = 0.001 moles

4. Calculate the percentage of sulphur in the organic compound:
- Mass of sulphur = Moles of sulphur x molar mass of sulphur = 0.001 x 32.1 = 0.0321 g
- Percentage of sulphur = (Mass of sulphur/Mass of organic compound) x 100 = (0.0321/0.32) x 100 = 10%

Therefore, the percentage of sulphur in the organic compound is 10%. Hence, option (A) is the correct answer.
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If 0.32 g of an organic compound containing sulphur produces 0.233g of...
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If 0.32 g of an organic compound containing sulphur produces 0.233g of BaSO₄. Then the percentage of sulphur in it isa)10b)15c)20d)25Correct answer is option 'A'. Can you explain this answer?
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