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When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)
[Atomic mass: Silver = 108, Bromine = 80]
[Atomic mass: Silver = 108, Bromine = 80]
Correct answer is '68'. Can you explain this answer?
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When 0.15 g of an organic compound was analyzed using Carius method fo...
To calculate the percentage of bromine in the organic compound, we need to first determine the number of moles of AgBr obtained from 0.15 g of the organic compound.
1. Calculate the number of moles of AgBr:
The molar mass of AgBr is the sum of the atomic masses of silver (Ag) and bromine (Br):
Molar mass of AgBr = 108 g/mol + 80 g/mol = 188 g/mol
Using the formula for calculating moles (moles = mass/molar mass), we can determine the number of moles of AgBr:
Moles of AgBr = 0.2397 g / 188 g/mol = 0.001274 moles
2. Calculate the number of moles of bromine:
Since AgBr has a 1:1 molar ratio with bromine, the number of moles of bromine is the same as the number of moles of AgBr:
Moles of bromine = 0.001274 moles
3. Calculate the mass of bromine:
The molar mass of bromine is 80 g/mol, so we can calculate the mass of bromine using the formula mass = moles × molar mass:
Mass of bromine = 0.001274 moles × 80 g/mol = 0.1019 g
4. Calculate the percentage of bromine:
The percentage of bromine is calculated by dividing the mass of bromine by the mass of the organic compound and multiplying by 100:
Percentage of bromine = (0.1019 g / 0.15 g) × 100 = 67.93%
Rounding off to the nearest integer, the percentage of bromine in the organic compound is 68%.
1. Calculate the number of moles of AgBr:
The molar mass of AgBr is the sum of the atomic masses of silver (Ag) and bromine (Br):
Molar mass of AgBr = 108 g/mol + 80 g/mol = 188 g/mol
Using the formula for calculating moles (moles = mass/molar mass), we can determine the number of moles of AgBr:
Moles of AgBr = 0.2397 g / 188 g/mol = 0.001274 moles
2. Calculate the number of moles of bromine:
Since AgBr has a 1:1 molar ratio with bromine, the number of moles of bromine is the same as the number of moles of AgBr:
Moles of bromine = 0.001274 moles
3. Calculate the mass of bromine:
The molar mass of bromine is 80 g/mol, so we can calculate the mass of bromine using the formula mass = moles × molar mass:
Mass of bromine = 0.001274 moles × 80 g/mol = 0.1019 g
4. Calculate the percentage of bromine:
The percentage of bromine is calculated by dividing the mass of bromine by the mass of the organic compound and multiplying by 100:
Percentage of bromine = (0.1019 g / 0.15 g) × 100 = 67.93%
Rounding off to the nearest integer, the percentage of bromine in the organic compound is 68%.
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When 0.15 g of an organic compound was analyzed using Carius method fo...
Moles of Br = Moles of AgBr obtained
Therefore, % of Br in the organic compound
⇒ Nearest integer = 68
Therefore, % of Br in the organic compound
⇒ Nearest integer = 68
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When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)[Atomic mass: Silver = 108, Bromine = 80]Correct answer is '68'. Can you explain this answer?
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When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)[Atomic mass: Silver = 108, Bromine = 80]Correct answer is '68'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)[Atomic mass: Silver = 108, Bromine = 80]Correct answer is '68'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)[Atomic mass: Silver = 108, Bromine = 80]Correct answer is '68'. Can you explain this answer?.
When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)[Atomic mass: Silver = 108, Bromine = 80]Correct answer is '68'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)[Atomic mass: Silver = 108, Bromine = 80]Correct answer is '68'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)[Atomic mass: Silver = 108, Bromine = 80]Correct answer is '68'. Can you explain this answer?.
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When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)[Atomic mass: Silver = 108, Bromine = 80]Correct answer is '68'. Can you explain this answer?, a detailed solution for When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)[Atomic mass: Silver = 108, Bromine = 80]Correct answer is '68'. Can you explain this answer? has been provided alongside types of When 0.15 g of an organic compound was analyzed using Carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ________. (Nearest integer)[Atomic mass: Silver = 108, Bromine = 80]Correct answer is '68'. Can you explain this answer? theory, EduRev gives you an
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