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In Duma's method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.
(Round off to the nearest integer)
[Given: Aqueous tension at 287 K = 14 mm of Hg]
(Round off to the nearest integer)
[Given: Aqueous tension at 287 K = 14 mm of Hg]
Correct answer is '19'. Can you explain this answer?
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In Dumas method of estimation of nitrogen, 0.1840 g of an organic comp...
Given data:
- Mass of organic compound = 0.1840 g
- Volume of nitrogen collected = 30 mL
- Temperature = 287 K
- Pressure = 758 mm Hg
- Aqueous tension at 287 K = 14 mm Hg
Dumas method of estimation of nitrogen:
The Dumas method is used to estimate the percentage composition of nitrogen in an organic compound. It involves the combustion of the organic compound in a current of oxygen gas. The nitrogen present in the compound is converted into nitrogen gas (N2), which is collected and measured.
Calculating the volume of nitrogen at standard conditions:
To calculate the volume of nitrogen at standard conditions (0°C and 1 atm), we need to apply the ideal gas equation:
PV = nRT
Where:
P = Pressure
V = Volume
n = moles of gas
R = Ideal gas constant
T = Temperature
First, we need to convert the pressure from mm Hg to atm:
1 atm = 760 mm Hg
So, the pressure becomes:
758 mm Hg / 760 mm Hg/atm = 0.997 atm
Next, we need to convert the volume from mL to L:
1 L = 1000 mL
So, the volume becomes:
30 mL / 1000 mL/L = 0.03 L
Now, we can calculate the moles of nitrogen using the ideal gas equation:
n = PV / RT
Where:
P = Pressure at standard conditions = 1 atm
V = Volume at standard conditions = 0.03 L
R = Ideal gas constant = 0.0821 L·atm/(mol·K)
T = Temperature at standard conditions = 273 K (0°C)
n = (1 atm) (0.03 L) / (0.0821 L·atm/(mol·K) * 273 K)
n = 0.00115 mol
Calculating the moles of nitrogen in the organic compound:
To calculate the moles of nitrogen in the organic compound, we can use the molar mass of nitrogen (N2) which is 28 g/mol.
Moles of nitrogen = Mass of nitrogen / Molar mass of nitrogen
Moles of nitrogen = 28 g/mol * 0.00115 mol
Moles of nitrogen = 0.0322 g
Calculating the percentage composition of nitrogen:
To calculate the percentage composition of nitrogen, we need to divide the mass of nitrogen in the compound by the mass of the compound and multiply by 100.
Percentage composition of nitrogen = (Mass of nitrogen / Mass of compound) * 100
Mass of compound = 0.1840 g
Mass of nitrogen = 0.0322 g
Percentage composition of nitrogen = (0.0322 g / 0.1840 g) * 100
Percentage composition of nitrogen = 17.5%
Rounding off to the nearest integer, the percentage composition of nitrogen in the compound is 18%.
- Mass of organic compound = 0.1840 g
- Volume of nitrogen collected = 30 mL
- Temperature = 287 K
- Pressure = 758 mm Hg
- Aqueous tension at 287 K = 14 mm Hg
Dumas method of estimation of nitrogen:
The Dumas method is used to estimate the percentage composition of nitrogen in an organic compound. It involves the combustion of the organic compound in a current of oxygen gas. The nitrogen present in the compound is converted into nitrogen gas (N2), which is collected and measured.
Calculating the volume of nitrogen at standard conditions:
To calculate the volume of nitrogen at standard conditions (0°C and 1 atm), we need to apply the ideal gas equation:
PV = nRT
Where:
P = Pressure
V = Volume
n = moles of gas
R = Ideal gas constant
T = Temperature
First, we need to convert the pressure from mm Hg to atm:
1 atm = 760 mm Hg
So, the pressure becomes:
758 mm Hg / 760 mm Hg/atm = 0.997 atm
Next, we need to convert the volume from mL to L:
1 L = 1000 mL
So, the volume becomes:
30 mL / 1000 mL/L = 0.03 L
Now, we can calculate the moles of nitrogen using the ideal gas equation:
n = PV / RT
Where:
P = Pressure at standard conditions = 1 atm
V = Volume at standard conditions = 0.03 L
R = Ideal gas constant = 0.0821 L·atm/(mol·K)
T = Temperature at standard conditions = 273 K (0°C)
n = (1 atm) (0.03 L) / (0.0821 L·atm/(mol·K) * 273 K)
n = 0.00115 mol
Calculating the moles of nitrogen in the organic compound:
To calculate the moles of nitrogen in the organic compound, we can use the molar mass of nitrogen (N2) which is 28 g/mol.
Moles of nitrogen = Mass of nitrogen / Molar mass of nitrogen
Moles of nitrogen = 28 g/mol * 0.00115 mol
Moles of nitrogen = 0.0322 g
Calculating the percentage composition of nitrogen:
To calculate the percentage composition of nitrogen, we need to divide the mass of nitrogen in the compound by the mass of the compound and multiply by 100.
Percentage composition of nitrogen = (Mass of nitrogen / Mass of compound) * 100
Mass of compound = 0.1840 g
Mass of nitrogen = 0.0322 g
Percentage composition of nitrogen = (0.0322 g / 0.1840 g) * 100
Percentage composition of nitrogen = 17.5%
Rounding off to the nearest integer, the percentage composition of nitrogen in the compound is 18%.
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Community Answer
In Dumas method of estimation of nitrogen, 0.1840 g of an organic comp...
In Duma's method of estimation of nitrogen. 0.184 g of an organic compound gave 30 mL of nitrogen which is collected at 287 K and 758 mm of Hg.
Given:
Aqueous tension at 287 K = 14 mm of Hg
Hence, actual pressure = (758 - 14) = 744 mm of Hg
Volume of nitrogen at STP
V = 27.935 mL
∵ 22,400 mL of N2 at STP weighs 28 g.
∵ 27.94 mL of N2 at STP weighs ((28/22,400) × 27.94) g = 0.0349 g
Hence, % of nitrogen
= 18.97%
≈ 19%
Given:
Aqueous tension at 287 K = 14 mm of Hg
Hence, actual pressure = (758 - 14) = 744 mm of Hg
Volume of nitrogen at STP
V = 27.935 mL
∵ 22,400 mL of N2 at STP weighs 28 g.
∵ 27.94 mL of N2 at STP weighs ((28/22,400) × 27.94) g = 0.0349 g
Hence, % of nitrogen
= 18.97%
≈ 19%
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In Dumas method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.(Round off to the nearest integer)[Given: Aqueous tension at 287 K = 14 mm of Hg]Correct answer is '19'. Can you explain this answer?
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In Dumas method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.(Round off to the nearest integer)[Given: Aqueous tension at 287 K = 14 mm of Hg]Correct answer is '19'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In Dumas method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.(Round off to the nearest integer)[Given: Aqueous tension at 287 K = 14 mm of Hg]Correct answer is '19'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Dumas method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.(Round off to the nearest integer)[Given: Aqueous tension at 287 K = 14 mm of Hg]Correct answer is '19'. Can you explain this answer?.
In Dumas method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.(Round off to the nearest integer)[Given: Aqueous tension at 287 K = 14 mm of Hg]Correct answer is '19'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In Dumas method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.(Round off to the nearest integer)[Given: Aqueous tension at 287 K = 14 mm of Hg]Correct answer is '19'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Dumas method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.(Round off to the nearest integer)[Given: Aqueous tension at 287 K = 14 mm of Hg]Correct answer is '19'. Can you explain this answer?.
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In Dumas method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.(Round off to the nearest integer)[Given: Aqueous tension at 287 K = 14 mm of Hg]Correct answer is '19'. Can you explain this answer?, a detailed solution for In Dumas method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.(Round off to the nearest integer)[Given: Aqueous tension at 287 K = 14 mm of Hg]Correct answer is '19'. Can you explain this answer? has been provided alongside types of In Dumas method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is ______.(Round off to the nearest integer)[Given: Aqueous tension at 287 K = 14 mm of Hg]Correct answer is '19'. Can you explain this answer? theory, EduRev gives you an
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