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Complete combustion of 750 g of an organic compound provides 420 g of CO2 and 210 g of H2O. The percentage composition of carbon and hydrogen in organic compound is 15.3 and ________, respectively. (Round off to the nearest integer)
Correct answer is '3'. Can you explain this answer?
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Complete combustion of 750 g of an organic compound provides 420 g of ...
Given:
- Mass of organic compound = 750 g
- Mass of CO2 produced = 420 g
- Mass of H2O produced = 210 g
- Percentage composition of carbon = 15.3%
To find:
- Percentage composition of hydrogen
Explanation:
To solve this problem, we need to use the concept of conservation of mass and the law of definite proportions.
1. Calculate the mass of carbon:
The mass of carbon in CO2 can be calculated using the ratio of the molar masses of carbon and CO2.
- Molar mass of carbon (C) = 12.01 g/mol
- Molar mass of CO2 = 12.01 g/mol + 2 * 16.00 g/mol = 44.01 g/mol
Using the ratio:
Mass of carbon = (Mass of CO2 / Molar mass of CO2) * Molar mass of carbon
= (420 g / 44.01 g/mol) * 12.01 g/mol
≈ 115.22 g
2. Calculate the mass of hydrogen:
The mass of hydrogen in H2O can be calculated using the ratio of the molar masses of hydrogen and H2O.
- Molar mass of hydrogen (H) = 1.01 g/mol
- Molar mass of H2O = 2 * 1.01 g/mol + 16.00 g/mol = 18.02 g/mol
Using the ratio:
Mass of hydrogen = (Mass of H2O / Molar mass of H2O) * Molar mass of hydrogen
= (210 g / 18.02 g/mol) * 1.01 g/mol
≈ 11.68 g
3. Calculate the percentage composition of hydrogen:
The percentage composition of an element in a compound is given by the formula:
Percentage composition = (Mass of element / Mass of compound) * 100
Using the formula:
Percentage composition of hydrogen = (Mass of hydrogen / Mass of organic compound) * 100
= (11.68 g / 750 g) * 100
≈ 1.56%
Rounding off to the nearest integer, the percentage composition of hydrogen is 2%.
Conclusion:
The percentage composition of carbon in the organic compound is 15.3% and the percentage composition of hydrogen is 2%.
- Mass of organic compound = 750 g
- Mass of CO2 produced = 420 g
- Mass of H2O produced = 210 g
- Percentage composition of carbon = 15.3%
To find:
- Percentage composition of hydrogen
Explanation:
To solve this problem, we need to use the concept of conservation of mass and the law of definite proportions.
1. Calculate the mass of carbon:
The mass of carbon in CO2 can be calculated using the ratio of the molar masses of carbon and CO2.
- Molar mass of carbon (C) = 12.01 g/mol
- Molar mass of CO2 = 12.01 g/mol + 2 * 16.00 g/mol = 44.01 g/mol
Using the ratio:
Mass of carbon = (Mass of CO2 / Molar mass of CO2) * Molar mass of carbon
= (420 g / 44.01 g/mol) * 12.01 g/mol
≈ 115.22 g
2. Calculate the mass of hydrogen:
The mass of hydrogen in H2O can be calculated using the ratio of the molar masses of hydrogen and H2O.
- Molar mass of hydrogen (H) = 1.01 g/mol
- Molar mass of H2O = 2 * 1.01 g/mol + 16.00 g/mol = 18.02 g/mol
Using the ratio:
Mass of hydrogen = (Mass of H2O / Molar mass of H2O) * Molar mass of hydrogen
= (210 g / 18.02 g/mol) * 1.01 g/mol
≈ 11.68 g
3. Calculate the percentage composition of hydrogen:
The percentage composition of an element in a compound is given by the formula:
Percentage composition = (Mass of element / Mass of compound) * 100
Using the formula:
Percentage composition of hydrogen = (Mass of hydrogen / Mass of organic compound) * 100
= (11.68 g / 750 g) * 100
≈ 1.56%
Rounding off to the nearest integer, the percentage composition of hydrogen is 2%.
Conclusion:
The percentage composition of carbon in the organic compound is 15.3% and the percentage composition of hydrogen is 2%.
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Community Answer
Complete combustion of 750 g of an organic compound provides 420 g of ...
44 gm of CO2 has 12 gm of carbon.
So, 420 gm of CO2 ⇒ 22/44 x 420
⇒ 1260/11 gm of carbon
⇒ 114.545 gm of carbon
So, %age of carbon = 114.545 / 750 x 100
≌ 15.3%
18 gm of H2O ⇒ 2 gm of H2
210 gm ⇒ 2/18 × 210
= 23.33 gm of H2
So, %age of H2
= 3.11%
≈ 3%
So, 420 gm of CO2 ⇒ 22/44 x 420
⇒ 1260/11 gm of carbon
⇒ 114.545 gm of carbon
So, %age of carbon = 114.545 / 750 x 100
≌ 15.3%
18 gm of H2O ⇒ 2 gm of H2
210 gm ⇒ 2/18 × 210
= 23.33 gm of H2
So, %age of H2
= 3.11%
≈ 3%
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Complete combustion of 750 g of an organic compound provides 420 g of CO2 and 210 g of H2O. The percentage composition of carbon and hydrogen in organic compound is 15.3 and ________, respectively. (Round off to the nearest integer)Correct answer is '3'. Can you explain this answer?
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