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120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:
- a)25 and 75
- b)40 and 60
- c)60 and 40
- d)75 and 25
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
120 g of an organic compound that contains only carbon and hydrogen gi...
Mass of the organic compound = 120 g
Mass of CO2 = 330 g
Moles of CO2 = 330/4 = 7.5
Mass of carbon = 7.5 × 12 = 90 g
Percentage of C =
= 75%
Mass of H2O = 270 g
Moles of H2O = 270/18 = 15
Mass of hydrogen = 15 × 2 = 30 g
Percentage of H =
= 25%
Mass of CO2 = 330 g
Moles of CO2 = 330/4 = 7.5
Mass of carbon = 7.5 × 12 = 90 g
Percentage of C =
= 75%Mass of H2O = 270 g
Moles of H2O = 270/18 = 15
Mass of hydrogen = 15 × 2 = 30 g
Percentage of H =
= 25%Free Test
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Community Answer
120 g of an organic compound that contains only carbon and hydrogen gi...
To find the percentage of carbon and hydrogen in the organic compound, we need to calculate the moles of carbon and hydrogen in the given compound.
Given:
Mass of the compound = 120 g
Mass of CO2 produced = 330 g
Mass of H2O produced = 270 g
Step 1: Calculate the moles of CO2 and H2O produced
Moles of CO2 = Mass of CO2 / Molar mass of CO2
Molar mass of CO2 = 12.01 g/mol (carbon) + (2 * 16.00 g/mol) (oxygen) = 44.01 g/mol
Moles of CO2 = 330 g / 44.01 g/mol = 7.5 mol
Moles of H2O = Mass of H2O / Molar mass of H2O
Molar mass of H2O = 2.02 g/mol (hydrogen) + 16.00 g/mol (oxygen) = 18.02 g/mol
Moles of H2O = 270 g / 18.02 g/mol = 15 mol
Step 2: Calculate the moles of carbon and hydrogen
Since there is no other element present in the compound, the remaining mass of the compound after the formation of CO2 and H2O is the mass of carbon and hydrogen.
Remaining mass of the compound = Mass of the compound - (Mass of CO2 + Mass of H2O)
Remaining mass of the compound = 120 g - (330 g + 270 g) = -480 g (negative because the mass is lost during combustion)
The negative value indicates that the given mass of the compound is insufficient to produce the given mass of CO2 and H2O. Therefore, we assume that the remaining mass of the compound is zero, and all the carbon and hydrogen in the compound have been converted to CO2 and H2O.
Moles of carbon = Moles of CO2 = 7.5 mol
Moles of hydrogen = Moles of H2O = 15 mol
Step 3: Calculate the percentage of carbon and hydrogen
Percentage of carbon = (Moles of carbon / Total moles) * 100
Percentage of carbon = (7.5 mol / (7.5 mol + 15 mol)) * 100 = 33.33%
Percentage of hydrogen = (Moles of hydrogen / Total moles) * 100
Percentage of hydrogen = (15 mol / (7.5 mol + 15 mol)) * 100 = 66.67%
Rounding off to the nearest whole number, we get:
Percentage of carbon = 33%
Percentage of hydrogen = 67%
Therefore, the correct answer is option D) 75% carbon and 25% hydrogen.
Given:
Mass of the compound = 120 g
Mass of CO2 produced = 330 g
Mass of H2O produced = 270 g
Step 1: Calculate the moles of CO2 and H2O produced
Moles of CO2 = Mass of CO2 / Molar mass of CO2
Molar mass of CO2 = 12.01 g/mol (carbon) + (2 * 16.00 g/mol) (oxygen) = 44.01 g/mol
Moles of CO2 = 330 g / 44.01 g/mol = 7.5 mol
Moles of H2O = Mass of H2O / Molar mass of H2O
Molar mass of H2O = 2.02 g/mol (hydrogen) + 16.00 g/mol (oxygen) = 18.02 g/mol
Moles of H2O = 270 g / 18.02 g/mol = 15 mol
Step 2: Calculate the moles of carbon and hydrogen
Since there is no other element present in the compound, the remaining mass of the compound after the formation of CO2 and H2O is the mass of carbon and hydrogen.
Remaining mass of the compound = Mass of the compound - (Mass of CO2 + Mass of H2O)
Remaining mass of the compound = 120 g - (330 g + 270 g) = -480 g (negative because the mass is lost during combustion)
The negative value indicates that the given mass of the compound is insufficient to produce the given mass of CO2 and H2O. Therefore, we assume that the remaining mass of the compound is zero, and all the carbon and hydrogen in the compound have been converted to CO2 and H2O.
Moles of carbon = Moles of CO2 = 7.5 mol
Moles of hydrogen = Moles of H2O = 15 mol
Step 3: Calculate the percentage of carbon and hydrogen
Percentage of carbon = (Moles of carbon / Total moles) * 100
Percentage of carbon = (7.5 mol / (7.5 mol + 15 mol)) * 100 = 33.33%
Percentage of hydrogen = (Moles of hydrogen / Total moles) * 100
Percentage of hydrogen = (15 mol / (7.5 mol + 15 mol)) * 100 = 66.67%
Rounding off to the nearest whole number, we get:
Percentage of carbon = 33%
Percentage of hydrogen = 67%
Therefore, the correct answer is option D) 75% carbon and 25% hydrogen.
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120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer?
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120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer?.
120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer?.
Solutions for 120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer?, a detailed solution for 120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of 120 g of an organic compound that contains only carbon and hydrogen gives 330 g of CO2 and 270 g of water on complete combustion. The percentage of carbon and hydrogen, respectively, is:a)25 and 75b)40 and 60c)60 and 40d)75 and 25Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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